RRB NTPC/ASM/CA/TA Exam > RRB NTPC/ASM/CA/TA Questions > A loss of10(1/2)%gets converted into a profit...
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A loss of 10(1/2)% gets converted into a profit of 11(3/5)% when the selling price is increased by ₹ 132.60. The cost price (in ₹) the article is:
- a)750
- b)800
- c)600
- d)500
Correct answer is option 'C'. Can you explain this answer?
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A loss of10(1/2)%gets converted into a profit of11(3/5)%when the selli...
Given Information:
- Loss of 10(1/2)% converts into a profit of 11(3/5)% when the selling price is increased by 132.60.
Let's assume:
- Cost price of the article = Rs. X
Calculating the Initial Selling Price:
- Let the initial selling price be Rs. Y
- Given, loss of 10(1/2)% = 21/2%
- Therefore, the selling price after the loss = X - (21/2)% of X = X - (21X/200) = 179X/200
- This selling price increased by Rs. 132.60 in order to get a profit of 11(3/5)%
- So, the selling price after the increase = 179X/200 + 132.60
Calculating the Final Selling Price:
- Profit of 11(3/5)% = 38/5%
- Therefore, the selling price after the profit = X + (38X/500) = 938X/500
Equating the Initial and Final Selling Prices:
- 179X/200 + 132.60 = 938X/500
- Solving this equation, we get X = 600
Therefore, the cost price of the article is Rs. 600 (Option C).
- Loss of 10(1/2)% converts into a profit of 11(3/5)% when the selling price is increased by 132.60.
Let's assume:
- Cost price of the article = Rs. X
Calculating the Initial Selling Price:
- Let the initial selling price be Rs. Y
- Given, loss of 10(1/2)% = 21/2%
- Therefore, the selling price after the loss = X - (21/2)% of X = X - (21X/200) = 179X/200
- This selling price increased by Rs. 132.60 in order to get a profit of 11(3/5)%
- So, the selling price after the increase = 179X/200 + 132.60
Calculating the Final Selling Price:
- Profit of 11(3/5)% = 38/5%
- Therefore, the selling price after the profit = X + (38X/500) = 938X/500
Equating the Initial and Final Selling Prices:
- 179X/200 + 132.60 = 938X/500
- Solving this equation, we get X = 600
Therefore, the cost price of the article is Rs. 600 (Option C).
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Community Answer
A loss of10(1/2)%gets converted into a profit of11(3/5)%when the selli...
Given:
A loss of 10(1/2)% gets converted into a profit of 11(3/5)% when the selling price is increased by ₹ 132.60
As we know,
SP = CP+CP × Profit %
SP = CP−CP × Loss %
Let CP of the article be 100a
Now,
SP for 1st case =100a − 100a × 10(1/2)%
= 89.5a
SP for 2nd case = 100a + 100a × 11(3/5)%
= 111.6a
According to the question,
111.6a− 89.5a = 132.6
⇒ 22.1a = 132.6
⇒ a = 132.622.1
⇒ a = 6
So, cost price = 100 × 6
= ₹ 600
∴ The cost price (in ₹) the article is 600.
A loss of 10(1/2)% gets converted into a profit of 11(3/5)% when the selling price is increased by ₹ 132.60
As we know,
SP = CP+CP × Profit %
SP = CP−CP × Loss %
Let CP of the article be 100a
Now,
SP for 1st case =100a − 100a × 10(1/2)%
= 89.5a
SP for 2nd case = 100a + 100a × 11(3/5)%
= 111.6a
According to the question,
111.6a− 89.5a = 132.6
⇒ 22.1a = 132.6
⇒ a = 132.622.1
⇒ a = 6
So, cost price = 100 × 6
= ₹ 600
∴ The cost price (in ₹) the article is 600.
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A loss of10(1/2)%gets converted into a profit of11(3/5)%when the selling price is increased by 132.60. The cost price (in ) the article is:a)750b)800c)600d)500Correct answer is option 'C'. Can you explain this answer?
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