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Two pipes M and N can fill a tank in 8 minutes and 12 minutes respectively. If both the pipes are opened simultaneously, after what time should N be closed so that the tank is full in 6 minutes?
  • a)
    1 min
  • b)
    2 min
  • c)
    3 min
  • d)
    4 min
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
Two pipes M and N can fill a tank in 8 minutes and 12 minutes respecti...
Let us assume that after x minutes pipe N is closed
(1/8 + 1/12)*x + (1/8)*(6 -x) = 1
Therefore, x = 3 minutes
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Community Answer
Two pipes M and N can fill a tank in 8 minutes and 12 minutes respecti...
Calculation:
To find the time after which pipe N should be closed, we need to consider the rate at which the tank is filled by both pipes M and N.
Let the tank's total capacity be 1 unit.

Rate of filling:
- Pipe M fills the tank in 8 minutes, so its rate of filling = 1/8 units per minute.
- Pipe N fills the tank in 12 minutes, so its rate of filling = 1/12 units per minute.
When both pipes are open:
- Combined rate of filling = 1/8 + 1/12 = 5/24 units per minute.

Time to fill the tank in 6 minutes:
To fill the tank in 6 minutes, the total amount filled in 6 minutes by both pipes should be equal to the tank's capacity, which is 1 unit.
Total amount filled in 6 minutes = (5/24) * t + (1/12) * (6-t) = 1, where t is the time after which pipe N should be closed.
Solving the equation:
- (5/24) * t + (1/12) * (6-t) = 1
- 5t/24 + (6-t)/12 = 1
- 5t/24 + 6/12 - t/12 = 1
- 5t/24 + 1/2 - t/12 = 1
- 5t/24 - t/12 = 1 - 1/2
- 5t/24 - 2t/24 = 1/2
- 3t/24 = 1/2
- t = 4
Therefore, N should be closed after 4 minutes so that the tank is full in 6 minutes.

Conclusion:
The correct answer is option C) 3 min.
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Two pipes M and N can fill a tank in 8 minutes and 12 minutes respectively. If both the pipes are opened simultaneously, after what time should N be closed so that the tank is full in 6 minutes?a)1 minb)2 minc)3 mind)4 minCorrect answer is option 'C'. Can you explain this answer?
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