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The actinoids exhibit more oxidation states in general than the lanthanoids. This is because:
  • a)
    The 5f orbitals are more buried than the 4f orbitals.
  • b)
    There is a similarity between 4f and 5f orbitals in their angular part of the wave function.
  • c)
    The actinoids are more reactive than the lanthanoids.
  • d)
    The 5f orbitals extend further from the nucleus than the 4f orbitals.
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The actinoids exhibit more oxidation states in general than the lantha...
Explanation:
1. 5f orbitals extend further from the nucleus: The main reason why actinoids exhibit more oxidation states compared to lanthanoids is that the 5f orbitals of actinoids extend further from the nucleus than the 4f orbitals of lanthanoids. This allows the actinoids to participate in a wider range of chemical reactions and form compounds in various oxidation states.
2. Greater accessibility of 5f orbitals: Due to the extended nature of the 5f orbitals, actinoid elements can easily lose or gain electrons to form different oxidation states. This flexibility in electron configuration leads to the observation of a larger number of oxidation states in actinoids compared to lanthanoids.
3. Electron configuration: The 5f orbitals are less shielded from the nuclear charge in actinoids, making them more accessible for chemical reactions. This increased accessibility of the 5f orbitals contributes to the ability of actinoids to exhibit a wide range of oxidation states.
4. Comparison with lanthanoids: In contrast, the 4f orbitals of lanthanoids are more buried within the electron cloud surrounding the nucleus, limiting their participation in chemical reactions and resulting in fewer observed oxidation states compared to actinoids.
In conclusion, the extended nature of the 5f orbitals in actinoids allows for greater accessibility and flexibility in electron configuration, leading to the observation of a wider range of oxidation states in actinoid elements.
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Community Answer
The actinoids exhibit more oxidation states in general than the lantha...
In actinoids, the outermost 5f orbitals are away from the nucleus. This makes them similar in energies to 6d and 7s orbitals. Thus, electrons can easily transition between these orbitals, and once they reach the valence orbital they can be ionized, This leads to the variability in oxidation states. In the case of lanthanoids, the outermost 4f orbitals are too close to the nucleus.
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The actinoids exhibit more oxidation states in general than the lanthanoids. This is because:a)The 5f orbitals are more buried than the 4f orbitals.b)There is a similarity between 4f and 5f orbitals in their angular part of the wave function.c)The actinoids are more reactive than the lanthanoids.d)The 5f orbitals extend further from the nucleus than the 4f orbitals.Correct answer is option 'D'. Can you explain this answer?
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The actinoids exhibit more oxidation states in general than the lanthanoids. This is because:a)The 5f orbitals are more buried than the 4f orbitals.b)There is a similarity between 4f and 5f orbitals in their angular part of the wave function.c)The actinoids are more reactive than the lanthanoids.d)The 5f orbitals extend further from the nucleus than the 4f orbitals.Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The actinoids exhibit more oxidation states in general than the lanthanoids. This is because:a)The 5f orbitals are more buried than the 4f orbitals.b)There is a similarity between 4f and 5f orbitals in their angular part of the wave function.c)The actinoids are more reactive than the lanthanoids.d)The 5f orbitals extend further from the nucleus than the 4f orbitals.Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The actinoids exhibit more oxidation states in general than the lanthanoids. This is because:a)The 5f orbitals are more buried than the 4f orbitals.b)There is a similarity between 4f and 5f orbitals in their angular part of the wave function.c)The actinoids are more reactive than the lanthanoids.d)The 5f orbitals extend further from the nucleus than the 4f orbitals.Correct answer is option 'D'. Can you explain this answer?.
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