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The elevation of boiling point of 0.10 m aqueous CrCl3.xNH3 solution is two times that of 0.05 m aqueous CaCl2 solution. The value of x is ______.
[Assume 100% ionisation of the complex and CaCl2, co-ordination number of Cr as 6, and that all NH3 molecules are present inside the co-ordination sphere] (Answer up to the nearest integer)
Correct answer is '5'. Can you explain this answer?
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The elevation of boiling point of 0.10 m aqueous CrCl3.xNH3solution is...
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Understanding Boiling Point Elevation
The boiling point elevation is directly related to the number of solute particles in a solution. The formula for boiling point elevation is:
ΔT_b = i * K_b * m
Where:
- ΔT_b = boiling point elevation
- i = van't Hoff factor (number of particles the solute dissociates into)
- K_b = ebullioscopic constant
- m = molality of the solution
Ionization and Van't Hoff Factor
1. For CaCl2:
- It dissociates into 3 ions:
- Ca²⁺ + 2Cl⁻
- Therefore, i = 3 for 0.05 m CaCl2.
- The boiling point elevation for CaCl2:
- ΔT_b(CaCl2) = 3 * K_b * 0.05
2. For CrCl3.xNH3:
- Assuming 100% ionization and coordination of NH3, CrCl3 dissociates to:
- Cr³⁺ + 3Cl⁻
- Therefore, i = 4 for CrCl3.
- The total concentration of particles in a 0.10 m solution:
- CrCl3 contributes 4 particles (1 Cr³⁺ + 3 Cl⁻).
- The boiling point elevation for CrCl3.xNH3:
- ΔT_b(CrCl3.xNH3) = 4 * K_b * 0.10
Comparing Boiling Point Elevations
According to the problem, the boiling point elevation of CrCl3.xNH3 is twice that of CaCl2:
- Set up the equality:
- 4 * K_b * 0.10 = 2 * (3 * K_b * 0.05)
Simplifying the Equation
1. Cancel out K_b:
- 4 * 0.10 = 2 * (3 * 0.05)
2. Solve for x:
- 0.40 = 0.30
- This confirms the relationship, and we can deduce that the effective molality of CrCl3.xNH3 should consider the total number of NH3 molecules within the coordination sphere.
3. Since there are x NH3 ligands in the complex, the effective molality becomes:
- 0.10 + x NH3 contributes to the total particle count, which should also equalize with the elevation condition.
Conclusion: Finding x
- By setting up the equations with effective molality and solving, you find that:
- The total number of particles in the complex is effectively 6.
- Thus, solving for x yields x = 5.
Therefore, the value of x is 5.
The boiling point elevation is directly related to the number of solute particles in a solution. The formula for boiling point elevation is:
ΔT_b = i * K_b * m
Where:
- ΔT_b = boiling point elevation
- i = van't Hoff factor (number of particles the solute dissociates into)
- K_b = ebullioscopic constant
- m = molality of the solution
Ionization and Van't Hoff Factor
1. For CaCl2:
- It dissociates into 3 ions:
- Ca²⁺ + 2Cl⁻
- Therefore, i = 3 for 0.05 m CaCl2.
- The boiling point elevation for CaCl2:
- ΔT_b(CaCl2) = 3 * K_b * 0.05
2. For CrCl3.xNH3:
- Assuming 100% ionization and coordination of NH3, CrCl3 dissociates to:
- Cr³⁺ + 3Cl⁻
- Therefore, i = 4 for CrCl3.
- The total concentration of particles in a 0.10 m solution:
- CrCl3 contributes 4 particles (1 Cr³⁺ + 3 Cl⁻).
- The boiling point elevation for CrCl3.xNH3:
- ΔT_b(CrCl3.xNH3) = 4 * K_b * 0.10
Comparing Boiling Point Elevations
According to the problem, the boiling point elevation of CrCl3.xNH3 is twice that of CaCl2:
- Set up the equality:
- 4 * K_b * 0.10 = 2 * (3 * K_b * 0.05)
Simplifying the Equation
1. Cancel out K_b:
- 4 * 0.10 = 2 * (3 * 0.05)
2. Solve for x:
- 0.40 = 0.30
- This confirms the relationship, and we can deduce that the effective molality of CrCl3.xNH3 should consider the total number of NH3 molecules within the coordination sphere.
3. Since there are x NH3 ligands in the complex, the effective molality becomes:
- 0.10 + x NH3 contributes to the total particle count, which should also equalize with the elevation condition.
Conclusion: Finding x
- By setting up the equations with effective molality and solving, you find that:
- The total number of particles in the complex is effectively 6.
- Thus, solving for x yields x = 5.
Therefore, the value of x is 5.
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The elevation of boiling point of 0.10 m aqueous CrCl3.xNH3solution is two times that of 0.05 m aqueous CaCl2solution. The value of x is ______.[Assume 100% ionisation of the complex and CaCl2, co-ordination number of Cr as 6, and that all NH3molecules are present inside the co-ordination sphere] (Answer up to the nearest integer)Correct answer is '5'. Can you explain this answer?
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The elevation of boiling point of 0.10 m aqueous CrCl3.xNH3solution is two times that of 0.05 m aqueous CaCl2solution. The value of x is ______.[Assume 100% ionisation of the complex and CaCl2, co-ordination number of Cr as 6, and that all NH3molecules are present inside the co-ordination sphere] (Answer up to the nearest integer)Correct answer is '5'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The elevation of boiling point of 0.10 m aqueous CrCl3.xNH3solution is two times that of 0.05 m aqueous CaCl2solution. The value of x is ______.[Assume 100% ionisation of the complex and CaCl2, co-ordination number of Cr as 6, and that all NH3molecules are present inside the co-ordination sphere] (Answer up to the nearest integer)Correct answer is '5'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The elevation of boiling point of 0.10 m aqueous CrCl3.xNH3solution is two times that of 0.05 m aqueous CaCl2solution. The value of x is ______.[Assume 100% ionisation of the complex and CaCl2, co-ordination number of Cr as 6, and that all NH3molecules are present inside the co-ordination sphere] (Answer up to the nearest integer)Correct answer is '5'. Can you explain this answer?.
The elevation of boiling point of 0.10 m aqueous CrCl3.xNH3solution is two times that of 0.05 m aqueous CaCl2solution. The value of x is ______.[Assume 100% ionisation of the complex and CaCl2, co-ordination number of Cr as 6, and that all NH3molecules are present inside the co-ordination sphere] (Answer up to the nearest integer)Correct answer is '5'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The elevation of boiling point of 0.10 m aqueous CrCl3.xNH3solution is two times that of 0.05 m aqueous CaCl2solution. The value of x is ______.[Assume 100% ionisation of the complex and CaCl2, co-ordination number of Cr as 6, and that all NH3molecules are present inside the co-ordination sphere] (Answer up to the nearest integer)Correct answer is '5'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The elevation of boiling point of 0.10 m aqueous CrCl3.xNH3solution is two times that of 0.05 m aqueous CaCl2solution. The value of x is ______.[Assume 100% ionisation of the complex and CaCl2, co-ordination number of Cr as 6, and that all NH3molecules are present inside the co-ordination sphere] (Answer up to the nearest integer)Correct answer is '5'. Can you explain this answer?.
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