UGC NET Exam > UGC NET Questions > The wavelength of the radiation emitted, when...
Start Learning for Free
The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)
- a)91 nm
- b)9.1 x 10-8 nm
- c)406 nm
- d)192 nm
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The wavelength of the radiation emitted, when in hydrogen atom electro...
Z=1 for the Hydrogen atom.
So,
So,
Free Test
FREE
| Start Free Test |
Community Answer
The wavelength of the radiation emitted, when in hydrogen atom electro...
Explanation:
Bohr's Model:
- According to Bohr's model, when an electron falls from infinity to the stationary state 1 in a hydrogen atom, the wavelength of the radiation emitted can be calculated using the Rydberg formula.
- The Rydberg constant is given as 1.097 x 10^7 m^-1.
Calculating Wavelength:
- The formula to calculate the wavelength of the emitted radiation is given by: 1/λ = R(1/n1^2 - 1/n2^2)
- Here, n1 = 1 (initial state), n2 = ∞ (final state), R = Rydberg constant.
- Plugging in the values, we get: 1/λ = 1.097 x 10^7 (1/1 - 1/∞)
- As 1/∞ approaches 0, the equation simplifies to: 1/λ = 1.097 x 10^7
- Therefore, the wavelength of the radiation emitted when the electron falls from infinity to stationary state 1 in a hydrogen atom is 91 nm.
Final Answer:
- The correct answer is option 'A': 91 nm.
Bohr's Model:
- According to Bohr's model, when an electron falls from infinity to the stationary state 1 in a hydrogen atom, the wavelength of the radiation emitted can be calculated using the Rydberg formula.
- The Rydberg constant is given as 1.097 x 10^7 m^-1.
Calculating Wavelength:
- The formula to calculate the wavelength of the emitted radiation is given by: 1/λ = R(1/n1^2 - 1/n2^2)
- Here, n1 = 1 (initial state), n2 = ∞ (final state), R = Rydberg constant.
- Plugging in the values, we get: 1/λ = 1.097 x 10^7 (1/1 - 1/∞)
- As 1/∞ approaches 0, the equation simplifies to: 1/λ = 1.097 x 10^7
- Therefore, the wavelength of the radiation emitted when the electron falls from infinity to stationary state 1 in a hydrogen atom is 91 nm.
Final Answer:
- The correct answer is option 'A': 91 nm.
Attention UGC NET Students!
To make sure you are not studying endlessly, EduRev has designed UGC NET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UGC NET.
|
Explore Courses for UGC NET exam
|
|
Similar UGC NET Doubts
Top Courses for UGC NETView all
The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer?
Question Description
The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer?.
The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer?.
Solutions for The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for UGC NET.
Download more important topics, notes, lectures and mock test series for UGC NET Exam by signing up for free.
Here you can find the meaning of The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The wavelength of the radiation emitted, when in hydrogen atom electron falls from infinity to stationary state 1, would be (Rydberg constant = 1.097×107 m-1)a)91 nmb)9.1 x 10-8 nmc)406 nmd)192 nmCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice UGC NET tests.
|
|
Explore Courses for UGC NET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup