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A 3-phase induction motor runs at 3% slip and develops mechanical power equal to 10 kW. The air gap power is:
- a)9.7 kW
- b)(10/0.97) kW
- c)100.30 kW
- d)10.3 kW
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A 3-phase induction motor runs at 3% slip and develops mechanical powe...
Calculation of Air Gap Power
The mechanical power developed by the motor is given as 10 kW, and the slip is 3%. To find the air gap power, we need to calculate the input power to the motor first.
Calculation of Input Power
Input Power = Output Power / Efficiency
Given, Output Power = Mechanical Power = 10 kW
Efficiency of the motor is typically around 0.97 (97%)
Therefore, Input Power = 10 kW / 0.97 = 10.31 kW
Calculation of Air Gap Power
Air Gap Power = Input Power - Output Power
Air Gap Power = 10.31 kW - 10 kW = 0.31 kW
Therefore, the air gap power is approximately 0.31 kW, which is equivalent to (10/0.97) kW or 9.7 kW. Hence, option B is the correct answer.
The mechanical power developed by the motor is given as 10 kW, and the slip is 3%. To find the air gap power, we need to calculate the input power to the motor first.
Calculation of Input Power
Input Power = Output Power / Efficiency
Given, Output Power = Mechanical Power = 10 kW
Efficiency of the motor is typically around 0.97 (97%)
Therefore, Input Power = 10 kW / 0.97 = 10.31 kW
Calculation of Air Gap Power
Air Gap Power = Input Power - Output Power
Air Gap Power = 10.31 kW - 10 kW = 0.31 kW
Therefore, the air gap power is approximately 0.31 kW, which is equivalent to (10/0.97) kW or 9.7 kW. Hence, option B is the correct answer.
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Community Answer
A 3-phase induction motor runs at 3% slip and develops mechanical powe...
Given,
s = 3%
Pm = 10 kW
Pg = ?
The relation between air gap power, rotor copper loss, and mechanical power developed by the rotor are given below.
Pg:Pcu:Pm = 1:s:(1−s)
Where,
Pg = Input power to the rotor from stator or airgap power
Pcu = Rotor copper loss
Pm = Mechanical power developed by the rotor
s = Slip speed of a motor
⇒ Pg:Pm=1:(1−s)
s = 3%
Pm = 10 kW
Pg = ?
The relation between air gap power, rotor copper loss, and mechanical power developed by the rotor are given below.
Pg:Pcu:Pm = 1:s:(1−s)
Where,
Pg = Input power to the rotor from stator or airgap power
Pcu = Rotor copper loss
Pm = Mechanical power developed by the rotor
s = Slip speed of a motor
⇒ Pg:Pm=1:(1−s)
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A 3-phase induction motor runs at 3% slip and develops mechanical power equal to 10 kW. The air gap power is:a)9.7 kWb)(10/0.97) kWc)100.30 kWd)10.3 kWCorrect answer is option 'B'. Can you explain this answer?
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