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An alternating voltage,v, has a periodic time of0.01sand a peak value of40V. When timetis zero,v=−20V.Express the instantaneous voltage in the form v = Vmsin(ωt±ø).a)b)c)d)Correct answer is option 'A'. Can you explain this answer? for RRB NTPC/ASM/CA/TA 2024 is part of RRB NTPC/ASM/CA/TA preparation. The Question and answers have been prepared according to the RRB NTPC/ASM/CA/TA exam syllabus. Information about An alternating voltage,v, has a periodic time of0.01sand a peak value of40V. When timetis zero,v=−20V.Express the instantaneous voltage in the form v = Vmsin(ωt±ø).a)b)c)d)Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for RRB NTPC/ASM/CA/TA 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An alternating voltage,v, has a periodic time of0.01sand a peak value of40V. When timetis zero,v=−20V.Express the instantaneous voltage in the form v = Vmsin(ωt±ø).a)b)c)d)Correct answer is option 'A'. Can you explain this answer?.

Solutions for An alternating voltage,v, has a periodic time of0.01sand a peak value of40V. When timetis zero,v=−20V.Express the instantaneous voltage in the form v = Vmsin(ωt±ø).a)b)c)d)Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for RRB NTPC/ASM/CA/TA. Download more important topics, notes, lectures and mock test series for RRB NTPC/ASM/CA/TA Exam by signing up for free.

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