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A series RLC circuit has the resistance of 16 Ω and the current lags behind the voltage by 45°. If the voltage across inductor is thrice the voltage across capacitor, then find the value of inductance reactance in ohms?
  • a)
    5
  • b)
    15
  • c)
    8
  • d)
    24
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A series RLC circuit has the resistance of 16 Ω and the current ...
Ohms, the inductance of 0.1 H, and the capacitance of 0.01 F. The circuit is connected to an AC voltage source with a frequency of 60 Hz.

To analyze the circuit, we can calculate the impedance of the circuit using the formula:

Z = √(R^2 + (Xl - Xc)^2)

Where:
Z = impedance
R = resistance = 16 ohms
Xl = inductive reactance = 2πfL = 2π(60)(0.1) = 37.7 ohms
Xc = capacitive reactance = 1 / (2πfC) = 1 / (2π(60)(0.01)) = 26.5 ohms

Plugging in the values:
Z = √(16^2 + (37.7 - 26.5)^2)
Z = √(256 + 11.2^2)
Z = √(256 + 125.44)
Z = √381.44
Z = 19.54 ohms

Therefore, the impedance of the series RLC circuit is 19.54 ohms.
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Community Answer
A series RLC circuit has the resistance of 16 Ω and the current ...
Given R = 10 Ω
Also given that voltage lags current hence circuit has lagging power factor
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A series RLC circuit has the resistance of 16 Ω and the current lags behind the voltage by 45°. If the voltage across inductor is thrice the voltage across capacitor, then find the value of inductance reactance in ohms?a)5b)15c)8d)24Correct answer is option 'D'. Can you explain this answer?
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