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A 33 kV, 50 Hz, 60 MVA turbine generator has the following sequence reactances in pu.
X1=0.1
X2=0.13
X0=0.04
X1=0.1
X2=0.13
X0=0.04
The value of inductive reactance in ohms to be inserted in the neutral connection to limit the current for a single line to ground fault to that of a three-phase fault is ________ (round off up to two decimal places)
- a)2.18Ω
- b)0.18Ω
- c)2.40Ω
- d)3.25Ω
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A 33 kV, 50 Hz, 60 MVA turbine generator has the following sequence re...
To calculate the inductive reactance in ohms to be inserted in the neutral connection, we can use the formula:
Xn = (3 * X1 * X2) / (3 * X1 + X2 + 2 * X0)
Given:
X1 = 0.1
X2 = 0.13
X0 = 0.04
Plugging these values into the formula:
Xn = (3 * 0.1 * 0.13) / (3 * 0.1 + 0.13 + 2 * 0.04)
Xn = 0.039 / (0.3 + 0.13 + 0.08)
Xn = 0.039 / 0.51
Xn ≈ 0.076
Therefore, the value of the inductive reactance in ohms to be inserted in the neutral connection is approximately 0.076 ohms.
Xn = (3 * X1 * X2) / (3 * X1 + X2 + 2 * X0)
Given:
X1 = 0.1
X2 = 0.13
X0 = 0.04
Plugging these values into the formula:
Xn = (3 * 0.1 * 0.13) / (3 * 0.1 + 0.13 + 2 * 0.04)
Xn = 0.039 / (0.3 + 0.13 + 0.08)
Xn = 0.039 / 0.51
Xn ≈ 0.076
Therefore, the value of the inductive reactance in ohms to be inserted in the neutral connection is approximately 0.076 ohms.
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Community Answer
A 33 kV, 50 Hz, 60 MVA turbine generator has the following sequence re...
Given,
X1=0.1 pu
X2=0.13 pu
X0=0.04 pu
In a single line to ground (LG) fault, the fault current is,
Fault current for three phase fault,
Given that both the fault currents are equal.
Base kV = 33 kV
Base MVA = 60 MVA
X1=0.1 pu
X2=0.13 pu
X0=0.04 pu
In a single line to ground (LG) fault, the fault current is,
Fault current for three phase fault,
Given that both the fault currents are equal.
Base kV = 33 kV
Base MVA = 60 MVA
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A 33 kV, 50 Hz, 60 MVA turbine generator has the following sequence reactances in pu.X1=0.1X2=0.13X0=0.04The value of inductive reactance in ohms to be inserted in the neutral connection to limit the current for a single line to ground fault to that of a three-phase fault is ________ (round off up to two decimal places)a)2.18Ωb)0.18Ωc)2.40Ωd)3.25ΩCorrect answer is option 'B'. Can you explain this answer?
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A 33 kV, 50 Hz, 60 MVA turbine generator has the following sequence reactances in pu.X1=0.1X2=0.13X0=0.04The value of inductive reactance in ohms to be inserted in the neutral connection to limit the current for a single line to ground fault to that of a three-phase fault is ________ (round off up to two decimal places)a)2.18Ωb)0.18Ωc)2.40Ωd)3.25ΩCorrect answer is option 'B'. Can you explain this answer? for RRB NTPC/ASM/CA/TA 2024 is part of RRB NTPC/ASM/CA/TA preparation. The Question and answers have been prepared according to the RRB NTPC/ASM/CA/TA exam syllabus. Information about A 33 kV, 50 Hz, 60 MVA turbine generator has the following sequence reactances in pu.X1=0.1X2=0.13X0=0.04The value of inductive reactance in ohms to be inserted in the neutral connection to limit the current for a single line to ground fault to that of a three-phase fault is ________ (round off up to two decimal places)a)2.18Ωb)0.18Ωc)2.40Ωd)3.25ΩCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for RRB NTPC/ASM/CA/TA 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 33 kV, 50 Hz, 60 MVA turbine generator has the following sequence reactances in pu.X1=0.1X2=0.13X0=0.04The value of inductive reactance in ohms to be inserted in the neutral connection to limit the current for a single line to ground fault to that of a three-phase fault is ________ (round off up to two decimal places)a)2.18Ωb)0.18Ωc)2.40Ωd)3.25ΩCorrect answer is option 'B'. Can you explain this answer?.
A 33 kV, 50 Hz, 60 MVA turbine generator has the following sequence reactances in pu.X1=0.1X2=0.13X0=0.04The value of inductive reactance in ohms to be inserted in the neutral connection to limit the current for a single line to ground fault to that of a three-phase fault is ________ (round off up to two decimal places)a)2.18Ωb)0.18Ωc)2.40Ωd)3.25ΩCorrect answer is option 'B'. Can you explain this answer? for RRB NTPC/ASM/CA/TA 2024 is part of RRB NTPC/ASM/CA/TA preparation. The Question and answers have been prepared according to the RRB NTPC/ASM/CA/TA exam syllabus. Information about A 33 kV, 50 Hz, 60 MVA turbine generator has the following sequence reactances in pu.X1=0.1X2=0.13X0=0.04The value of inductive reactance in ohms to be inserted in the neutral connection to limit the current for a single line to ground fault to that of a three-phase fault is ________ (round off up to two decimal places)a)2.18Ωb)0.18Ωc)2.40Ωd)3.25ΩCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for RRB NTPC/ASM/CA/TA 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 33 kV, 50 Hz, 60 MVA turbine generator has the following sequence reactances in pu.X1=0.1X2=0.13X0=0.04The value of inductive reactance in ohms to be inserted in the neutral connection to limit the current for a single line to ground fault to that of a three-phase fault is ________ (round off up to two decimal places)a)2.18Ωb)0.18Ωc)2.40Ωd)3.25ΩCorrect answer is option 'B'. Can you explain this answer?.
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