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A solid metal cube of edge length 2 cm is moving in a positive y direction at a constant speed of 6 m/s. There is a uniform magnetic field of 0.1 T in the positive z-direction. The potential difference between the two faces of the cube perpendicular to the x-axis, is _____mV.
Correct answer is '12'. Can you explain this answer?
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A solid metal cube of edge length 2 cm is moving in a positive y direc...
Understanding the Problem
To determine the potential difference across the cube due to its motion in a magnetic field, we will use the concept of electromagnetic induction.
Key Parameters
- Edge Length (L): 2 cm = 0.02 m
- Speed (v): 6 m/s
- Magnetic Field (B): 0.1 T
Formula for Induced EMF
The induced electromotive force (EMF) in a conductor moving through a magnetic field is given by the formula:
EMF = B * L * v
where:
- B is the magnetic field strength,
- L is the length of the conductor (cube edge length in this case),
- v is the velocity of the conductor.
Calculating Induced EMF
1. Convert Units:
- Edge length, L = 0.02 m
- Speed, v = 6 m/s
- Magnetic field, B = 0.1 T
2. Substituting Values:
EMF = 0.1 T * 0.02 m * 6 m/s
3. Calculate:
EMF = 0.1 * 0.02 * 6 = 0.012 V
4. Convert to Millivolts:
EMF = 0.012 V = 12 mV
Conclusion
Thus, the potential difference between the two faces of the cube perpendicular to the x-axis is 12 mV. This result illustrates how motion in a magnetic field can induce a voltage across conductive materials.
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A solid metal cube of edge length 2 cm is moving in a positive y direc...
Potential difference between two faces perpendicular to x-axis will be
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In a thin rectangular metallic strip a constant current I flows along the positive x-direction, as shown in the figure. The length, width and thickness of the strip are l, w and d, respectively.A uniform magnetic fieldis applied on the strip along the positive y-direction. Due to this, the charge carriers experience anet deflection along the z-direction. This results in accumulation of charge carriers on the surface PQRS and appearance of equal and opposite charges on the face opposite to PQRS. A potential difference along the z-direction is thus developed. Charge accumulation continues until the magnetic force is balanced by the electric force. The current is assumed to be uniformly distributed on the cross-section of the strip and carried by electrons.Q.7.Consider two different metallic strips (1 and 2) of same dimensions (length l, width w and thickness d) with carrier densities n1 and n2, respectively. Strip 1 is placed in magnetic field B1 and strip 2 is placed in magnetic field B2, both along positive y-directions. Then V1 and V2 are the potential differences developed between K and M in strips 1 and 2, respectively. Assuming that the current I is the same for both the strips, the correct option(s) is(ar e)

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A solid metal cube of edge length 2 cm is moving in a positive y direction at a constant speed of 6 m/s. There is a uniform magnetic field of 0.1 T in the positive z-direction. The potential difference between the two faces of the cube perpendicular to the x-axis, is _____mV.Correct answer is '12'. Can you explain this answer?
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