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If the average age of A and B is 44 years and the ratio of the age of A to that of B is 5 : 6, what was the ratio of the age of A to that of B 16 years back?
  • a)
    1 : 2
  • b)
    2 : 3
  • c)
    3 : 4
  • d)
    4 : 5
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
If the average age of A and B is 44 years and the ratio of the age of ...
Sum of the current ages = 44 × 2 = 88 years


So the answer = 40 – 16 : 48 – 16 = 24 : 32 = 3 : 4
Hence, Option C is correct.
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Most Upvoted Answer
If the average age of A and B is 44 years and the ratio of the age of ...
Understanding the Problem
To solve the problem, we need to find the ages of A and B based on the information given.

Given Information
- Average age of A and B = 44 years
- Ratio of the age of A to B = 5 : 6

Calculating Individual Ages
- Let the age of A = 5x and age of B = 6x.
- The average age is given by:
\[
\text{Average} = \frac{\text{Age of A} + \text{Age of B}}{2} = 44
\]
- Substituting the ages in the equation:
\[
\frac{5x + 6x}{2} = 44
\]
- Simplifying the equation:
\[
\frac{11x}{2} = 44 \implies 11x = 88 \implies x = 8
\]
- Therefore:
- Age of A = \(5 \times 8 = 40\) years
- Age of B = \(6 \times 8 = 48\) years

Calculating Ages 16 Years Back
- Now, we need to find the ages of A and B 16 years back:
- Age of A 16 years back = \(40 - 16 = 24\) years
- Age of B 16 years back = \(48 - 16 = 32\) years

Finding the Ratio 16 Years Back
- The ratio of the ages of A to B 16 years back is:
\[
\text{Ratio} = \frac{24}{32} = \frac{3}{4}
\]
- Hence, the ratio of the age of A to B 16 years back is **3:4**.

Conclusion
The correct answer is option 'C' (3:4).
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Question Description
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