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A cantilever of 4 m span carries a uniformly distributed load of 5 kN/m on the whole span. Find the value of maximum deflection in the beam. Take E = 2 ×105 N/mm2 and moment of inertia of beam section = 2 × 108 N/mm2.
  • a)
    5.33 mm
  • b)
    4 mm
  • c)
    16 mm
  • d)
    10.66 mm
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A cantilever of 4 m span carries a uniformly distributed load of 5 kN/...
Concept:
The maximum deflection of a cantilever beam with uniformly distributed load is given by,

Here,
w = Uniformly distributed load
L = Length of the beam
E = Modulus of Elasticity
I = Moment of Inertia
Calculation:
Given that,
w = 5 kN/m
L = 4 m = 4000 mm
E = 2 ×105 N/mm2
I = 2 × 108 N/mm2.
Deflection,
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A cantilever of 4 m span carries a uniformly distributed load of 5 kN/m on the whole span. Find the value of maximum deflection in the beam. Take E = 2 ×105N/mm2and moment of inertia of beam section = 2 × 108N/mm2.a)5.33 mmb)4 mmc)16 mmd)10.66 mmCorrect answer is option 'B'. Can you explain this answer?
Question Description
A cantilever of 4 m span carries a uniformly distributed load of 5 kN/m on the whole span. Find the value of maximum deflection in the beam. Take E = 2 ×105N/mm2and moment of inertia of beam section = 2 × 108N/mm2.a)5.33 mmb)4 mmc)16 mmd)10.66 mmCorrect answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A cantilever of 4 m span carries a uniformly distributed load of 5 kN/m on the whole span. Find the value of maximum deflection in the beam. Take E = 2 ×105N/mm2and moment of inertia of beam section = 2 × 108N/mm2.a)5.33 mmb)4 mmc)16 mmd)10.66 mmCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A cantilever of 4 m span carries a uniformly distributed load of 5 kN/m on the whole span. Find the value of maximum deflection in the beam. Take E = 2 ×105N/mm2and moment of inertia of beam section = 2 × 108N/mm2.a)5.33 mmb)4 mmc)16 mmd)10.66 mmCorrect answer is option 'B'. Can you explain this answer?.
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