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The mole fraction of glucose (C6H12O6) in an aqueous binary solution is 0.1. The mass percentage of water in it, is ________. (Nearest integer)
Correct answer is '47'. Can you explain this answer?
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The mole fraction of glucose (C6H12O6) in an aqueous binary solution i...
Mole fraction of glucose in aqueous solution = 0.1
Mass of glucose in the solution = 0.1
Mole fraction of water in aqueous solution = 1 - 0.1 = 0.9
Mass of water in the solution = 0.9 × 18 = 162 g
Total mass of the solution = 180 g + 162 g = 342 g
Mass percentage of water = (162 g/342 g) × 100 = 47.368% ≈ 47%
Mass of glucose in the solution = 0.1
× 180 = 180 g
Mole fraction of water in aqueous solution = 1 - 0.1 = 0.9
Mass of water in the solution = 0.9 × 18 = 162 g
Total mass of the solution = 180 g + 162 g = 342 g
Mass percentage of water = (162 g/342 g) × 100 = 47.368% ≈ 47%
Most Upvoted Answer
The mole fraction of glucose (C6H12O6) in an aqueous binary solution i...
Given:
Mole fraction of glucose (C6H12O6) in the solution = 0.1
To find:
The mass percentage of water in the solution
Solution:
To find the mass percentage of water in the solution, we need to determine the mole fraction of water first.
Step 1: Determine the mole fraction of water
Since it is a binary solution, the mole fraction of water can be calculated as follows:
Mole fraction of water (H2O) = 1 - Mole fraction of glucose (C6H12O6)
Given that the mole fraction of glucose is 0.1, we can calculate the mole fraction of water as:
Mole fraction of water (H2O) = 1 - 0.1 = 0.9
Step 2: Calculate the mass percentage of water
The mass percentage of water can be calculated using the following formula:
Mass percentage of water = (Mole fraction of water * Molar mass of water) / (Mole fraction of water * Molar mass of water + Mole fraction of glucose * Molar mass of glucose) * 100
The molar mass of water (H2O) is 18 g/mol and the molar mass of glucose (C6H12O6) is 180 g/mol.
Substituting the values into the formula:
Mass percentage of water = (0.9 * 18) / (0.9 * 18 + 0.1 * 180) * 100
= (16.2) / (16.2 + 18) * 100
= 16.2 / 34.2 * 100
≈ 47 (nearest integer)
Hence, the mass percentage of water in the solution is approximately 47%.
Mole fraction of glucose (C6H12O6) in the solution = 0.1
To find:
The mass percentage of water in the solution
Solution:
To find the mass percentage of water in the solution, we need to determine the mole fraction of water first.
Step 1: Determine the mole fraction of water
Since it is a binary solution, the mole fraction of water can be calculated as follows:
Mole fraction of water (H2O) = 1 - Mole fraction of glucose (C6H12O6)
Given that the mole fraction of glucose is 0.1, we can calculate the mole fraction of water as:
Mole fraction of water (H2O) = 1 - 0.1 = 0.9
Step 2: Calculate the mass percentage of water
The mass percentage of water can be calculated using the following formula:
Mass percentage of water = (Mole fraction of water * Molar mass of water) / (Mole fraction of water * Molar mass of water + Mole fraction of glucose * Molar mass of glucose) * 100
The molar mass of water (H2O) is 18 g/mol and the molar mass of glucose (C6H12O6) is 180 g/mol.
Substituting the values into the formula:
Mass percentage of water = (0.9 * 18) / (0.9 * 18 + 0.1 * 180) * 100
= (16.2) / (16.2 + 18) * 100
= 16.2 / 34.2 * 100
≈ 47 (nearest integer)
Hence, the mass percentage of water in the solution is approximately 47%.
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The mole fraction of glucose (C6H12O6) in an aqueous binary solution is 0.1. The mass percentage of water in it, is ________. (Nearest integer)Correct answer is '47'. Can you explain this answer?
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