SSC CGL Exam > SSC CGL Questions > If 2nd June 2013 is Sunday then which day was...
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If 2nd June 2013 is Sunday then which day was on 2nd June 2010?
- a)Wednesday
- b)Friday
- c)Thursday
- d)Saturday
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
If 2nd June 2013 is Sunday then which day was on 2nd June 2010?a)Wedne...
Consider from 2nd June 2010 to 2nd June 2013 we have total 2 non leap year and one leap year so number of odd days are 1 + 1 + 2 = 4 so 2nd June 2010 must be 4 days back from Sunday and that day is Wednesday.
From Zeller's Formula:
f = k + [13 x m - 1/ 5 ] + D + [D/4] + [C/4] - 2 x C.
In this case k = 2 (since 2nd June)
Month m = 4 (As march = 1, April = 2, May = 3, June = 4 )
D is the last two digit of year here D = 10 (As year is 2010)
C is 1 st two digit of century here C = 20 (As year is 2010)
f = 2 + [13 x 4 - 1 / 5] + 10 + [10/ 4] + [ 20/4] - 2 x 20.
f = 2 + [51/5] + 10 +[2.5] + [5] - 40.
f = 2 + 10 + 10 + 2 + 5 - 40 = -11
This - ve value of f can be made positive by adding multiple of 7
So f = - 11 + 14 = 3
When divided by 7 we will get remainder 3, hence number of odd days is 3,
So 2nd June 2010 is 3 days more than Monday, i.e Wednesday.
From Zeller's Formula:
f = k + [13 x m - 1/ 5 ] + D + [D/4] + [C/4] - 2 x C.
In this case k = 2 (since 2nd June)
Month m = 4 (As march = 1, April = 2, May = 3, June = 4 )
D is the last two digit of year here D = 10 (As year is 2010)
C is 1 st two digit of century here C = 20 (As year is 2010)
f = 2 + [13 x 4 - 1 / 5] + 10 + [10/ 4] + [ 20/4] - 2 x 20.
f = 2 + [51/5] + 10 +[2.5] + [5] - 40.
f = 2 + 10 + 10 + 2 + 5 - 40 = -11
This - ve value of f can be made positive by adding multiple of 7
So f = - 11 + 14 = 3
When divided by 7 we will get remainder 3, hence number of odd days is 3,
So 2nd June 2010 is 3 days more than Monday, i.e Wednesday.
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Community Answer
If 2nd June 2013 is Sunday then which day was on 2nd June 2010?a)Wedne...
Calculation:
To determine the day on 2nd June 2010, we need to consider the number of days between 2nd June 2010 and 2nd June 2013.
Step 1: Calculate the number of days between 2nd June 2010 and 2nd June 2013.
2013 - 2010 = 3 years
Since 2012 is a leap year, it has one extra day. Therefore, adding one day for the leap year:
3 years + 1 day = 3 years + 1 day = 1096 days
Step 2: Divide the total days by 7 to find out the remainder.
1096 ÷ 7 = 156 remainder 4
Step 3: Find out which day corresponds to the remainder obtained in Step 2.
Starting from Sunday as 0, Monday as 1, Tuesday as 2, Wednesday as 3, Thursday as 4, Friday as 5, and Saturday as 6:
So, the remainder 4 corresponds to Thursday.
Therefore, if 2nd June 2013 is Sunday, then 2nd June 2010 was Thursday.
To determine the day on 2nd June 2010, we need to consider the number of days between 2nd June 2010 and 2nd June 2013.
Step 1: Calculate the number of days between 2nd June 2010 and 2nd June 2013.
2013 - 2010 = 3 years
Since 2012 is a leap year, it has one extra day. Therefore, adding one day for the leap year:
3 years + 1 day = 3 years + 1 day = 1096 days
Step 2: Divide the total days by 7 to find out the remainder.
1096 ÷ 7 = 156 remainder 4
Step 3: Find out which day corresponds to the remainder obtained in Step 2.
Starting from Sunday as 0, Monday as 1, Tuesday as 2, Wednesday as 3, Thursday as 4, Friday as 5, and Saturday as 6:
So, the remainder 4 corresponds to Thursday.
Therefore, if 2nd June 2013 is Sunday, then 2nd June 2010 was Thursday.
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If 2nd June 2013 is Sunday then which day was on 2nd June 2010?a)Wednesdayb)Fridayc)Thursdayd)SaturdayCorrect answer is option 'A'. Can you explain this answer?
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