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The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?
  • a)
    m + 4
  • b)
    n + 6
  • c)
    n + 3
  • d)
    m + 5
  • e)
    n + 4
Correct answer is option 'E'. Can you explain this answer?
Most Upvoted Answer
The average of 5 consecutive integers starting with m as the first int...
Approach: Work with a numerical example
The fastest way to solve problems of this kind is to take numerical examples.
Let the 5 consecutive integers be 1, 2, 3, 4, and 5.
The average of 5 consecutive integers from 1 to 5 is 3.
Therefore, the value of m is 1 and the value of n is 3.
Because m = 1, m + 2 = 3
9 consecutive integers starting from m + 2 will be 3, 4, ... , 11
The average of positive integers from 3 to 11 is 7.
We know n = 3. So, 7 has to be (n + 4).
Choice E is the correct answer.
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