GMAT Exam  >  GMAT Questions  >  The average of 5 consecutive integers startin... Start Learning for Free
The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?
  • a)
    m + 4
  • b)
    n + 6
  • c)
    n + 3
  • d)
    m + 5
  • e)
    n + 4
Correct answer is option 'E'. Can you explain this answer?
Verified Answer
The average of 5 consecutive integers starting with m as the first int...
Approach: Work with a numerical example
The fastest way to solve problems of this kind is to take numerical examples.
Let the 5 consecutive integers be 1, 2, 3, 4, and 5.
The average of 5 consecutive integers from 1 to 5 is 3.
Therefore, the value of m is 1 and the value of n is 3.
Because m = 1, m + 2 = 3
9 consecutive integers starting from m + 2 will be 3, 4, ... , 11
The average of positive integers from 3 to 11 is 7.
We know n = 3. So, 7 has to be (n + 4).
Choice E is the correct answer.
View all questions of this test
Most Upvoted Answer
The average of 5 consecutive integers starting with m as the first int...
Understanding the Problem
To find the average of 5 consecutive integers starting with m, we first define these integers:
- m, m+1, m+2, m+3, m+4
The average (n) of these integers can be calculated as:
- Average (n) = (m + (m+1) + (m+2) + (m+3) + (m+4)) / 5
This simplifies to:
- n = (5m + 10) / 5 = m + 2
Finding the Average of 9 Consecutive Integers
Now, we need to find the average of 9 consecutive integers starting with (m + 2):
- The integers are: (m + 2), (m + 3), (m + 4), (m + 5), (m + 6), (m + 7), (m + 8), (m + 9), (m + 10)
The average of these integers is:
- Average = ((m + 2) + (m + 3) + (m + 4) + (m + 5) + (m + 6) + (m + 7) + (m + 8) + (m + 9) + (m + 10)) / 9
This simplifies to:
- Average = (9m + 54) / 9 = m + 6
Relating it to n
Since we previously found that n = m + 2, we can express the average of the 9 integers in terms of n:
- Average = m + 6 = (n - 2) + 6 = n + 4
Conclusion
Thus, the average of the 9 consecutive integers starting with (m + 2) is:
- n + 4
This confirms that the correct answer is option 'E'.
Explore Courses for GMAT exam

Top Courses for GMAT

Question Description
The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?a)m + 4b)n + 6c)n + 3d)m + 5e)n + 4Correct answer is option 'E'. Can you explain this answer? for GMAT 2025 is part of GMAT preparation. The Question and answers have been prepared according to the GMAT exam syllabus. Information about The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?a)m + 4b)n + 6c)n + 3d)m + 5e)n + 4Correct answer is option 'E'. Can you explain this answer? covers all topics & solutions for GMAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?a)m + 4b)n + 6c)n + 3d)m + 5e)n + 4Correct answer is option 'E'. Can you explain this answer?.
Solutions for The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?a)m + 4b)n + 6c)n + 3d)m + 5e)n + 4Correct answer is option 'E'. Can you explain this answer? in English & in Hindi are available as part of our courses for GMAT. Download more important topics, notes, lectures and mock test series for GMAT Exam by signing up for free.
Here you can find the meaning of The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?a)m + 4b)n + 6c)n + 3d)m + 5e)n + 4Correct answer is option 'E'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?a)m + 4b)n + 6c)n + 3d)m + 5e)n + 4Correct answer is option 'E'. Can you explain this answer?, a detailed solution for The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?a)m + 4b)n + 6c)n + 3d)m + 5e)n + 4Correct answer is option 'E'. Can you explain this answer? has been provided alongside types of The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?a)m + 4b)n + 6c)n + 3d)m + 5e)n + 4Correct answer is option 'E'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The average of 5 consecutive integers starting with m as the first integer is n. What is the average of 9 consecutive integers that start with (m + 2)?a)m + 4b)n + 6c)n + 3d)m + 5e)n + 4Correct answer is option 'E'. Can you explain this answer? tests, examples and also practice GMAT tests.
Explore Courses for GMAT exam

Top Courses for GMAT

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev