UGC NET Exam > UGC NET Questions > The data obtained from an enzyme-catalyzed re...
Start Learning for Free
The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0 is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:
- a)0.02
- b)0.04
- c)0.08
- d)0.06
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
The data obtained from an enzyme-catalyzed reaction are plotted as 1/r...
The graphical presentation of the Michaelis-Menten equation is given below:
- The plot is given as a plot between 1/Rate(1/v) on the y-axis and 1/substrate conc.(1/[S]) on the X-axis where the slope is m and the intercept is c
- Thus if we plot (1/Rate)VS(1/substrate conc) in the above plot then we get a gradient of the equation as km/Vmax which is equal to m and the intercept (c) is 1/vmax.
- If we take the ratio of slope over intercept from the following plot then we get Michaelis-Menten Constant.
= km - Now, given the slope and y-intercept obtained from this plot are 50 and 100, respectively.
- Thus,
- From the above two relations, we get
km = 0.5 - Thus, from equation (i) we get,
- Hence, If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is T.O.N =
= 0.01/0.5mM
= 0.02 mM-1
Hence, option 1 is correct.
= 0.02 mM-1
Hence, option 1 is correct.
Free Test
FREE
| Start Free Test |
Community Answer
The data obtained from an enzyme-catalyzed reaction are plotted as 1/r...
Calculation of Turnover Number:
Given:
- Slope = 50
- Y-intercept = 100
- Enzyme concentration = 0.5 mM
Formula:
Turnover number (kcat) = Slope / Enzyme concentration
Calculation:
- Using the equation for the plot: 1/rate = 50 * (1/[S]0) + 100
- Since the y-intercept is 100, when 1/[S]0 = 0, 1/rate = 100
- Therefore, the rate at infinite substrate concentration is 100
- The enzyme concentration is 0.5 mM, so the turnover number is 100 / 0.5 = 200 mM-1
So, the correct answer is 0.02 (as turnover number is 0.02 mM-1).
Given:
- Slope = 50
- Y-intercept = 100
- Enzyme concentration = 0.5 mM
Formula:
Turnover number (kcat) = Slope / Enzyme concentration
Calculation:
- Using the equation for the plot: 1/rate = 50 * (1/[S]0) + 100
- Since the y-intercept is 100, when 1/[S]0 = 0, 1/rate = 100
- Therefore, the rate at infinite substrate concentration is 100
- The enzyme concentration is 0.5 mM, so the turnover number is 100 / 0.5 = 200 mM-1
So, the correct answer is 0.02 (as turnover number is 0.02 mM-1).
Attention UGC NET Students!
To make sure you are not studying endlessly, EduRev has designed UGC NET study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UGC NET.
|
Explore Courses for UGC NET exam
|
|
Top Courses for UGC NETView all
The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer?
Question Description
The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer?.
The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer?.
Solutions for The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for UGC NET.
Download more important topics, notes, lectures and mock test series for UGC NET Exam by signing up for free.
Here you can find the meaning of The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer?, a detailed solution for The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The data obtained from an enzyme-catalyzed reaction are plotted as 1/rate against 1/[S]0, where [S]0is the initial substrate concentration. The slope and y-intercept obtained from this plot are 50 and 100, respectively. If the enzyme concentration used in this reaction is 0.5 mM, then the turnover number (in mM-1) of the enzyme is:a)0.02b)0.04c)0.08d)0.06Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice UGC NET tests.
|
|
Explore Courses for UGC NET exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup