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Calculate the number of aluminium ions present in 0.51 gm of aluminium oxide.?
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Calculate the number of aluminium ions present in 0.51 gm of aluminium...
1 mole of aluminium oxide, Al2O3 = 2 x 27 + 3 x 16 = 102u = 102 gm That is 102 gm Al2O3 has 6.023 x 1023 Al2O3 molecules Or, 0.51 gm Al2O3 has = (6.023 x 1023 x 0.51) / 102 = 3.01 x 1021 Al2O3 molecules. We know 1 molecule of Al2O3 has 2Al+++ ions. Hence, 0.51 gm Al2O3 has = 2 x 3.01 x 1021 Al+++ ions = 6.023 x 1021 aluminium ions.
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Calculate the number of aluminium ions present in 0.51 gm of aluminium oxide.?
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