If reduced bearing of a line is N87anddeg;W , its whole circle bearing will be:a)87anddeg;b)93anddeg;c)3anddeg;d)273anddeg;Correct answer is option 'D'. Can you explain this answer?

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Civil Engineering (CE) Exam > Civil Engineering (CE) Questions > If reduced bearing of a line is N87°W , i...

If reduced bearing of a line is N87°W , its whole circle bearing will be:

a)
87°
b)
93°
c)
3°
d)
273°

Correct answer is option 'D'. Can you explain this answer?

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If reduced bearing of a line is N87°W , its whole circle bearing w...

Whole circle Bearing system:

In this system, the bearing of the line is measured from the north in clockwise direction.
Thus whole circle bearing system (WCB) of a line is the horizontal angle which the line makes with the north end of the reference meridian.
The WCB of a line can vary from 0° to 360°.

Quadrantal Bearing system:

The quadrantal bearing (QB) of a line is the acuate angle which the line makes with the meridian.
Quadrantal bearing is measured either from north end or south end as the case may be i.e. whichever is nearer to the line. The quadrantal bearing of a line can vary from 0° to 90°

Conversion table for WCB and QB:

Given,
Reduced Bearing = N87°W
∵ Reduced bearing exists in the 4th coordinate, so WCB of line
WCB = 360 - 87° = 273°

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If reduced bearing of a line is N87°W , its whole circle bearing will be:a)87°b)93°c)3°d)273°Correct answer is option 'D'. Can you explain this answer?

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