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Of the following, the correct statements regarding Uranium are
A. Most stable oxidation state of Uranium is +6
B. In uranocene its oxidation state is +5
C. In UO2+ the colour is due to LMCT
D. Electronic configuration of Uranium is [Rn] 5f3 6d1 7s2
  • a)
    A and D only
  • b)
    A, C and D only
  • c)
    A, B and D only
  • d)
    B, C  and D only
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Of the following, the correct statements regarding Uranium areA. Most ...
A. Most stable oxidation state of Uranium is +6.
  • This statement is correct. Uranium has complex electronic configuration, 5f3 6d1 7s2 in its ground state. Therefore, uranium exhibit wide range of oxidation state, but it is most stable in it's +6 oxidation state. In +6 oxidation state uranium loses all of its electrons and attain nearest nobel gas configuration i.e. of radon [Rn]. Achieving a noble gas electron configuration is energetically favorable because it results in a stable, closed-shell electron arrangement.
  • In the +6 oxidation state, uranium forms the uranyl ion, UO22+. This ion is relatively small in size and has a high charge density, making it more stable compared to other oxidation states. 
B. In uranocene, its oxidation state is +5.
  • This statement is incorrect. Uranocene, is a organometallic compound, contains uranium in the oxidation state of +4. The chemical formula for uranocene is typically written as (C5H5)2U, shows the presence of two cyclopentadienyl (C5H5)- ligands coordinated to the uranium atom forming a "sandwich structure" where uranium atom is situated between the two cyclopentadienyl ring. Each uranium atom in uranocene has four electrons in its outermost shell, which forms coordination bonds with the cyclopentadienyl ligands, resulting in its +4 oxidation state.
​C. In UO2+ the color is due to LMCT.
  • This statement is correct. UO2+ exhibit color due to LMCT involving the oxygen atoms of the ligand and the uranium metal atom. In UO2+, uranium is in the +6 oxidation state where uranium has a relatively high number of unoccupied orbitals and can accept electrons from the surrounding ligands during electronic transitions. Oxygen has available lone pairs of electrons in its outermost shell that can participate in bonding with the uranium atom. When UO2+ absorbs visible light, it often involves the promotion of an electron from a non-bonding orbital of oxygen to empty orbital of uranium (e.g., a vacant 5f orbital). This transition is a LMCT process, as it involves the transfer of electron density from the ligand to the metal center.
​D. Electronic configuration of Uranium is [Rn] 5f3 6d1 7s2.
  • This statement is correct. The electronic configuration of uranium is indeed [Rn] 5f3 6d1 7s2, where [Rn] represents the electron configuration of radon, the noble gas that precedes uranium in the periodic table. The presence of 5f³ and 6d¹ electrons in its outermost shells accounts for uranium's ability to form compounds in various oxidation states.
Hence, the correct statements regarding Uranium are A, C, and D. 
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Most Upvoted Answer
Of the following, the correct statements regarding Uranium areA. Most ...
Explanation:
Most stable oxidation state of Uranium is +6
- Uranium typically exhibits multiple oxidation states, with the most stable being +6.
- In this state, Uranium forms compounds such as uranium hexafluoride (UF6) and uranyl nitrate (UO2(NO3)2).
In uranocene its oxidation state is +5
- Uranocene is a compound containing Uranium in the +5 oxidation state.
- This compound is known for its unique sandwich-like structure with two cyclooctatetraenyl ligands bound to the Uranium atom.
In UO2+ the colour is due to LMCT
- The color of UO2+ (uranyl cation) is due to Ligand-to-Metal Charge Transfer (LMCT).
- This means that the absorption of light causes an electron to transfer from a ligand orbital to a metal orbital, resulting in the observed color.
Electronic configuration of Uranium is [Rn] 5f3 6d1 7s2
- Uranium has the electronic configuration [Rn] 5f3 6d1 7s2, with the 5f and 6d orbitals being the primary valence orbitals involved in its chemistry.
- The presence of these orbitals leads to the diverse chemistry and oxidation states observed in Uranium compounds.
Therefore, the correct statements regarding Uranium are A, C, and D.
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Of the following, the correct statements regarding Uranium areA. Most stable oxidation state of Uranium is +6B.In uranocene its oxidation state is +5C. In UO2+thecolour is due to LMCTD.Electronic configuration of Uranium is[Rn] 5f36d17s2a)A and D onlyb)A, C and D onlyc)A, B and D onlyd)B, C and D onlyCorrect answer is option 'B'. Can you explain this answer?
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