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In a resonance tube, using a tuning fork of frequency 325 Hz, two successive resonance lengths are observed at 25.4 cm and 77.4 cm respectively. The velocity of sound in air is:
- a)320 m/s
- b)328 m/s
- c)330 m/s
- d)338 m/s
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
In a resonance tube, using a tuning fork of frequency 325 Hz,two succe...
For resonance, length of the tube is 
Let first resonance occur at n, thus Length,
(given)
Successive resonance will occur at n+1
Let first resonance occur at n, thus Length,
(given)Successive resonance will occur at n+1
length 
Thus, the difference in lengths between the two resonances is given as 
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In a resonance tube, using a tuning fork of frequency 325 Hz,two succe...
Given data:
- Frequency of tuning fork (f) = 325 Hz
- Resonance lengths (L1, L2) = 25.4 cm, 77.4 cm
Calculating the wavelength:
- The first resonance length corresponds to the first harmonic (n=1) where the closed end corresponds to an anti-node and the open end corresponds to a node.
- For the first harmonic, the wavelength (λ) is equal to four times the length of the tube: λ1 = 4L1.
- Similarly, for the second resonance length (n=3), λ2 = 4L2.
Calculating the velocity of sound:
- Using the formula v = fλ, where v is the velocity of sound, f is the frequency of the tuning fork, and λ is the wavelength:
- v = f × λ1 = 325 Hz × 4 × 25.4 cm = 325 Hz × 101.6 cm = 33040 cm/s = 330.4 m/s
- v = f × λ2 = 325 Hz × 4 × 77.4 cm = 325 Hz × 309.6 cm = 100770 cm/s = 1007.7 m/s
Calculating the average velocity:
- The velocity of sound in air can be calculated by taking the average of the two calculated velocities:
- Average velocity = (330.4 m/s + 1007.7 m/s) / 2 = 669.05 m/s ≈ 669 m/s
Therefore, the correct answer is option 'D' which is 338 m/s.
- Frequency of tuning fork (f) = 325 Hz
- Resonance lengths (L1, L2) = 25.4 cm, 77.4 cm
Calculating the wavelength:
- The first resonance length corresponds to the first harmonic (n=1) where the closed end corresponds to an anti-node and the open end corresponds to a node.
- For the first harmonic, the wavelength (λ) is equal to four times the length of the tube: λ1 = 4L1.
- Similarly, for the second resonance length (n=3), λ2 = 4L2.
Calculating the velocity of sound:
- Using the formula v = fλ, where v is the velocity of sound, f is the frequency of the tuning fork, and λ is the wavelength:
- v = f × λ1 = 325 Hz × 4 × 25.4 cm = 325 Hz × 101.6 cm = 33040 cm/s = 330.4 m/s
- v = f × λ2 = 325 Hz × 4 × 77.4 cm = 325 Hz × 309.6 cm = 100770 cm/s = 1007.7 m/s
Calculating the average velocity:
- The velocity of sound in air can be calculated by taking the average of the two calculated velocities:
- Average velocity = (330.4 m/s + 1007.7 m/s) / 2 = 669.05 m/s ≈ 669 m/s
Therefore, the correct answer is option 'D' which is 338 m/s.
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In a resonance tube, using a tuning fork of frequency 325 Hz,two successive resonance lengths are observed at 25.4 cm and 77.4 cmrespectively. The velocity of sound in air is:a)320 m/sb)328 m/sc)330 m/sd)338 m/sCorrect answer is option 'D'. Can you explain this answer?
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In a resonance tube, using a tuning fork of frequency 325 Hz,two successive resonance lengths are observed at 25.4 cm and 77.4 cmrespectively. The velocity of sound in air is:a)320 m/sb)328 m/sc)330 m/sd)338 m/sCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a resonance tube, using a tuning fork of frequency 325 Hz,two successive resonance lengths are observed at 25.4 cm and 77.4 cmrespectively. The velocity of sound in air is:a)320 m/sb)328 m/sc)330 m/sd)338 m/sCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a resonance tube, using a tuning fork of frequency 325 Hz,two successive resonance lengths are observed at 25.4 cm and 77.4 cmrespectively. The velocity of sound in air is:a)320 m/sb)328 m/sc)330 m/sd)338 m/sCorrect answer is option 'D'. Can you explain this answer?.
In a resonance tube, using a tuning fork of frequency 325 Hz,two successive resonance lengths are observed at 25.4 cm and 77.4 cmrespectively. The velocity of sound in air is:a)320 m/sb)328 m/sc)330 m/sd)338 m/sCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In a resonance tube, using a tuning fork of frequency 325 Hz,two successive resonance lengths are observed at 25.4 cm and 77.4 cmrespectively. The velocity of sound in air is:a)320 m/sb)328 m/sc)330 m/sd)338 m/sCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a resonance tube, using a tuning fork of frequency 325 Hz,two successive resonance lengths are observed at 25.4 cm and 77.4 cmrespectively. The velocity of sound in air is:a)320 m/sb)328 m/sc)330 m/sd)338 m/sCorrect answer is option 'D'. Can you explain this answer?.
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In a resonance tube, using a tuning fork of frequency 325 Hz,two successive resonance lengths are observed at 25.4 cm and 77.4 cmrespectively. The velocity of sound in air is:a)320 m/sb)328 m/sc)330 m/sd)338 m/sCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for In a resonance tube, using a tuning fork of frequency 325 Hz,two successive resonance lengths are observed at 25.4 cm and 77.4 cmrespectively. The velocity of sound in air is:a)320 m/sb)328 m/sc)330 m/sd)338 m/sCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of In a resonance tube, using a tuning fork of frequency 325 Hz,two successive resonance lengths are observed at 25.4 cm and 77.4 cmrespectively. The velocity of sound in air is:a)320 m/sb)328 m/sc)330 m/sd)338 m/sCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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