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The weights of two friends A and B are in the ratio of 5 : 7 respectively. After some time, A’s weight increased by 20% and the combined weight of both of them increased by 16.67%. If B’s new weight is 40 kg, what was the old weight (in kg) of A?
  • a)
    25
  • b)
    28
  • c)
    31.50
  • d)
    35
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The weights of two friends A and B are in the ratio of 5 : 7 respectiv...
Loses 10 kg and B gains 15 kg. Now their weights are in the ratio of 3 : 8. What were the original weights of A and B?

Let's assume the original weight of A is 5x kg and the original weight of B is 7x kg.

After losing 10 kg, A's weight becomes (5x - 10) kg.
After gaining 15 kg, B's weight becomes (7x + 15) kg.

According to the given information, the new weights are in the ratio of 3 : 8, so we can write:

(5x - 10)/(7x + 15) = 3/8.

Cross-multiplying, we get:
8(5x - 10) = 3(7x + 15).

Simplifying, we get:
40x - 80 = 21x + 45.

Bringing like terms to one side, we get:
40x - 21x = 80 + 45,
19x = 125.

Dividing both sides by 19, we get:
x = 125/19.

Therefore, the original weight of A is:
5x = 5 * (125/19) = 325/19 kg.

And the original weight of B is:
7x = 7 * (125/19) = 455/19 kg.

Therefore, the original weights of A and B are 325/19 kg and 455/19 kg respectively.
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Community Answer
The weights of two friends A and B are in the ratio of 5 : 7 respectiv...
Let the old weights → A and B = 5x and 7x
New weight of A = 120% of 5x = 6x

New weight of B = 14x – 6x = 8x

Hence, option A is correct.
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The weights of two friends A and B are in the ratio of 5 : 7 respectively. After some time, A’s weight increased by 20% and the combined weight of both of them increased by 16.67%. If B’s new weight is 40 kg, what was the old weight (in kg) of A?a)25b)28c)31.50d)35Correct answer is option 'A'. Can you explain this answer?
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