Can you explain the answer of this question below:Number of nitrogen atoms present in 1.4 g of N2:A:6.023 X 1022B:6.023 X 1023C:3.012 X 1023D:3.012 X 1022The answer is a.

Question

Can you explain the answer of this question below:Number of nitrogen atoms present in 1.4 g of N2:&#8203;A:6.023 X 1022B:6.023 X 1023C:3.012 X 1023D:3.012 X 1022The answer is a.

Answer

D bcoz mass of N2 is 28 so no. Of atoms gets divided and it becomes 3.012 x 10^12

Answer

No. of nitrogen atoms in 14 g. of nitrogen=1 mole =6.023×10^23 atoms. So,No. of nitrogen atoms in 1.4 g. of nitrogen=6.023×10^23÷10 =6.023×10^22atoms

Answer

Number of atoms/Avogadro no.=given mass/molar mass=1.4/14=0.1 no. of atoms=Avogadro no×0.1

Answer

No. of mole of 1.4g N2 in = 1.4/28=1/20
no. of molecules of N2 = 1/20 × 6.023×10^23
since one molecule of N2 contains two atoms of nitrogen.
no. of atoms = 2×1/20 × 6.023×10^23
=6.023×10^22

Answer

A

Answer

6.03×10^22

Answer

Because 1 mole of any substance have 6.023×10^23 atoms

Answer

6.02*10 22

Answer

Calculating the number of nitrogen atoms in 1.4 g of N2:
To determine the number of nitrogen atoms present in 1.4 g of N2, we need to follow these steps:
1. Calculate the molar mass of N2:
The molar mass of N2 (nitrogen gas) is 28 g/mol (14 g/mol for each nitrogen atom).
2. Convert the given mass to moles:
Divide the given mass (1.4 g) by the molar mass of N2 (28 g/mol) to get the number of moles of N2.
Moles of N2 = 1.4 g / 28 g/mol = 0.05 mol
3. Use Avogadro's number to find the number of molecules:
Since N2 is a diatomic molecule, the number of molecules is the same as the number of moles of N2 (0.05 mol).
Number of N2 molecules = 0.05 mol
4. Calculate the number of nitrogen atoms:
Each N2 molecule contains 2 nitrogen atoms, so to find the number of nitrogen atoms, we need to multiply the number of N2 molecules by 2.
Number of nitrogen atoms = 0.05 mol x 2 = 0.1 mol
5. Convert moles to atoms:
Finally, we need to use Avogadro's number (6.023 x 10^23 atoms/mol) to convert moles to atoms.
Number of nitrogen atoms = 0.1 mol x 6.023 x 10^23 atoms/mol = 6.023 x 10^22 atoms
Therefore, the number of nitrogen atoms present in 1.4 g of N2 is 6.023 x 10^22 atoms.

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