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If 3.01× 1020 molecules are removed from 98 mg of H2SO4 then number of moles of H2SO4 left are
- a)0.1 x 10-3 mol
- b)0.5 x 10-3 mol
- c)1.66 x 10-3 mol
- d)9.95 x 10-3 mol
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
If3.01×1020molecules are removed from 98 mg ofH2SO4then number o...
Calculation:
- Given that 3.01 x 10^20 molecules are removed from 98 mg of H2SO4.
- The molar mass of H2SO4 is 98 g/mol.
- First, we need to calculate the number of moles in 98 mg of H2SO4.
- Number of moles = Mass / Molar mass
- Number of moles = 98 mg / 98 g/mol = 0.001 mol
After removing 3.01 x 10^20 molecules:
- The number of moles left in the sample can be calculated using the formula:
- Number of moles left = Initial number of moles - Number of moles removed
- Number of moles left = 0.001 mol - (3.01 x 10^20 / Avogadro's number)
- Number of moles left = 0.001 mol - (3.01 x 10^20 / 6.022 x 10^23)
- Number of moles left = 0.001 mol - 0.0005 mol = 0.0005 mol
Final Answer:
Therefore, the number of moles of H2SO4 left after removing 3.01 x 10^20 molecules is 0.0005 mol, which is equivalent to 0.5 x 10^-3 mol. Hence, the correct answer is option B.
- Given that 3.01 x 10^20 molecules are removed from 98 mg of H2SO4.
- The molar mass of H2SO4 is 98 g/mol.
- First, we need to calculate the number of moles in 98 mg of H2SO4.
- Number of moles = Mass / Molar mass
- Number of moles = 98 mg / 98 g/mol = 0.001 mol
After removing 3.01 x 10^20 molecules:
- The number of moles left in the sample can be calculated using the formula:
- Number of moles left = Initial number of moles - Number of moles removed
- Number of moles left = 0.001 mol - (3.01 x 10^20 / Avogadro's number)
- Number of moles left = 0.001 mol - (3.01 x 10^20 / 6.022 x 10^23)
- Number of moles left = 0.001 mol - 0.0005 mol = 0.0005 mol
Final Answer:
Therefore, the number of moles of H2SO4 left after removing 3.01 x 10^20 molecules is 0.0005 mol, which is equivalent to 0.5 x 10^-3 mol. Hence, the correct answer is option B.
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Community Answer
If3.01×1020molecules are removed from 98 mg ofH2SO4then number o...
Actual number of moles in 98mg of H2SO4 = 1x10-3 mol
Number of molecules in 10-3 mol of 98 mg of H2SO4= 6.023 x1020
Since 3.01 x 1020 are removed from 98 mg of H2SO4, so half of the molecules are left.
Numbre of moles left in 98 mg of H2SO4=
(1─0.5)x10-3
= 0.5x10-3 moles
Number of molecules in 10-3 mol of 98 mg of H2SO4= 6.023 x1020
Since 3.01 x 1020 are removed from 98 mg of H2SO4, so half of the molecules are left.
Numbre of moles left in 98 mg of H2SO4=
(1─0.5)x10-3
= 0.5x10-3 moles
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If3.01×1020molecules are removed from 98 mg ofH2SO4then number of moles ofH2SO4left area)0.1 x 10-3 molb)0.5 x 10-3 molc)1.66 x 10-3 mold)9.95 x 10-3 molCorrect answer is option 'B'. Can you explain this answer?
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If3.01×1020molecules are removed from 98 mg ofH2SO4then number of moles ofH2SO4left area)0.1 x 10-3 molb)0.5 x 10-3 molc)1.66 x 10-3 mold)9.95 x 10-3 molCorrect answer is option 'B'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about If3.01×1020molecules are removed from 98 mg ofH2SO4then number of moles ofH2SO4left area)0.1 x 10-3 molb)0.5 x 10-3 molc)1.66 x 10-3 mold)9.95 x 10-3 molCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If3.01×1020molecules are removed from 98 mg ofH2SO4then number of moles ofH2SO4left area)0.1 x 10-3 molb)0.5 x 10-3 molc)1.66 x 10-3 mold)9.95 x 10-3 molCorrect answer is option 'B'. Can you explain this answer?.
If3.01×1020molecules are removed from 98 mg ofH2SO4then number of moles ofH2SO4left area)0.1 x 10-3 molb)0.5 x 10-3 molc)1.66 x 10-3 mold)9.95 x 10-3 molCorrect answer is option 'B'. Can you explain this answer? for UGC NET 2024 is part of UGC NET preparation. The Question and answers have been prepared according to the UGC NET exam syllabus. Information about If3.01×1020molecules are removed from 98 mg ofH2SO4then number of moles ofH2SO4left area)0.1 x 10-3 molb)0.5 x 10-3 molc)1.66 x 10-3 mold)9.95 x 10-3 molCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for UGC NET 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If3.01×1020molecules are removed from 98 mg ofH2SO4then number of moles ofH2SO4left area)0.1 x 10-3 molb)0.5 x 10-3 molc)1.66 x 10-3 mold)9.95 x 10-3 molCorrect answer is option 'B'. Can you explain this answer?.
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If3.01×1020molecules are removed from 98 mg ofH2SO4then number of moles ofH2SO4left area)0.1 x 10-3 molb)0.5 x 10-3 molc)1.66 x 10-3 mold)9.95 x 10-3 molCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for If3.01×1020molecules are removed from 98 mg ofH2SO4then number of moles ofH2SO4left area)0.1 x 10-3 molb)0.5 x 10-3 molc)1.66 x 10-3 mold)9.95 x 10-3 molCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of If3.01×1020molecules are removed from 98 mg ofH2SO4then number of moles ofH2SO4left area)0.1 x 10-3 molb)0.5 x 10-3 molc)1.66 x 10-3 mold)9.95 x 10-3 molCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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