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Can you explain the answer of this question below:
125 ml of 8% w/w NaOH solution (sp. gravity 1) is added to 125 ml of 10% w/v HCl solution. The nature of resultant solution would be ____
  • A:
    Acidic
  • B:
    Basic
  • C:
    Neutral
  • D:
    None
The answer is a.
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Calculation of moles of NaOH and HCl:

Moles of NaOH = (8/100) x 125/40 = 0.25
Moles of HCl = (10/100) x 125/36.5 = 0.342

Since moles of HCl > moles of NaOH, all the NaOH will be consumed in the reaction and there will be some HCl remaining.

HCl + NaOH → NaCl + H2O

After the reaction, the final volume of the solution will be 125 + 125 = 250 mL.

Concentration of HCl in the final solution:

Concentration of HCl = (0.342 moles / 0.25 L) x (1 L / 0.25 L) x (1000 mL / 1 L) = 136.8 mL/L

pH of the final solution:

pH = -log[H+]
[H+] = concentration of HCl = 136.8 mM
pH = -log(136.8 x 10^-3) = 2.86

Since the pH of the final solution is less than 7, it is acidic. Therefore, the correct answer is option 'A' (acidic).
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Can you explain the answer of this question below:125 ml of 8% w/w NaOH solution (sp. gravity 1) is added to 125 ml of 10% w/v HCl solution. The nature of resultant solution would be ____A:AcidicB:BasicC:NeutralD:NoneThe answer is a.
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