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A class has two sections, the average marks of all the students in the class is 80. The average marks of all the students of Section A is 75 and the average marks of all the students of Section B is 90. What is the ratio of the number of students in Section A to that in section B?
  • a)
    1 : 1
  • b)
    1 : 2
  • c)
    2 : 1
  • d)
    3 : 2
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A class has two sections, the average marks of all the students in the...
Let the number of students in Section A = A
The number of students in Section B = B
75A + 90B = 80 × (A + B)
10B = 5A
A : B = 2 : 1
Hence, Option C is correct.
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Community Answer
A class has two sections, the average marks of all the students in the...
Calculation:
To find the ratio of the number of students in Section A to that in Section B, we can use the concept of weighted averages.
Let the number of students in Section A be 'x' and the number of students in Section B be 'y'.
Given:
Average marks of all students = 80
Average marks of Section A = 75
Average marks of Section B = 90
We can set up the following equation based on the averages:
(75x + 90y) / (x + y) = 80
Solving this equation, we get:
75x + 90y = 80x + 80y
10y = 5x
2y = x

Ratio Calculation:
The ratio of the number of students in Section A to that in Section B is:
x : y = 2 : 1
Therefore, the correct answer is option 2 : 1.
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A class has two sections, the average marks of all the students in the class is 80. The average marks of all the students of Section A is 75 and the average marks of all the students of Section B is 90. What is the ratio of the number of students in Section A to that in section B?a)1 : 1b)1 : 2c)2 : 1d)3 : 2Correct answer is option 'C'. Can you explain this answer?
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