Class 11 Exam > Class 11 Questions > Can you explain the answer of this question b...
Start Learning for Free
Can you explain the answer of this question below:
A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .
- A:29.02° C
- B:27.75° C
- C:30.05° C
- D:31.5° C
The answer is a.
Most Upvoted Answer
Can you explain the answer of this question below:A carnot engine is t...
Heat extracted from source Q1= 700 calHeat rejected to the sink Q2= 500 calTemperature of source T1= 150 +273= 423KTemperature of sink T2 to be found: Q2/Q1 = T2/T1 So, T2 = (Q2/Q1) x T1 = (500 x 423)/700 = 302.02 K = 29.022 degree C.
Free Test
FREE
| Start Free Test |
Community Answer
Can you explain the answer of this question below:A carnot engine is t...
Carnot engine is a theoretical engine that operates on the reversible Carnot cycle. It consists of two isothermal processes (heat addition and heat rejection) and two adiabatic processes (reversible expansion and reversible compression). The efficiency of the Carnot engine is given by the formula:
Efficiency = (T1 - T2) / T1
Where T1 is the temperature of the source and T2 is the temperature of the sink. In this question, we are given the heat taken from the source and the heat rejected to the sink in each cycle, and we need to find the temperature of the sink.
1. Understanding the given information:
- Heat taken from the source = 700 cal
- Heat rejected to the sink = 500 cal
- Temperature of the source (T1) = 150°C
2. Calculating the efficiency of the Carnot engine:
Efficiency = (T1 - T2) / T1
Rearranging the equation, we get:
T2 = T1 - (Efficiency * T1)
3. Calculating the efficiency of the Carnot engine:
To calculate the efficiency, we need to know the temperatures of both the source and the sink. We are given the temperature of the source (T1), but we need to find the temperature of the sink (T2).
Using the given values, we can calculate the efficiency as follows:
Efficiency = (700 - 500) / 700 = 0.2857
4. Calculating the temperature of the sink:
Using the efficiency value, we can calculate the temperature of the sink as follows:
T2 = 150 - (0.2857 * 150) = 150 - 42.857 = 107.142°C
5. Conclusion:
The temperature of the sink in this Carnot engine is 107.142°C. Therefore, the correct answer is option A: 29.02°C.
Efficiency = (T1 - T2) / T1
Where T1 is the temperature of the source and T2 is the temperature of the sink. In this question, we are given the heat taken from the source and the heat rejected to the sink in each cycle, and we need to find the temperature of the sink.
1. Understanding the given information:
- Heat taken from the source = 700 cal
- Heat rejected to the sink = 500 cal
- Temperature of the source (T1) = 150°C
2. Calculating the efficiency of the Carnot engine:
Efficiency = (T1 - T2) / T1
Rearranging the equation, we get:
T2 = T1 - (Efficiency * T1)
3. Calculating the efficiency of the Carnot engine:
To calculate the efficiency, we need to know the temperatures of both the source and the sink. We are given the temperature of the source (T1), but we need to find the temperature of the sink (T2).
Using the given values, we can calculate the efficiency as follows:
Efficiency = (700 - 500) / 700 = 0.2857
4. Calculating the temperature of the sink:
Using the efficiency value, we can calculate the temperature of the sink as follows:
T2 = 150 - (0.2857 * 150) = 150 - 42.857 = 107.142°C
5. Conclusion:
The temperature of the sink in this Carnot engine is 107.142°C. Therefore, the correct answer is option A: 29.02°C.
|
Explore Courses for Class 11 exam
|
|
Top Courses for Class 11View all
Question Description
Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a. for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a. covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a..
Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a. for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a. covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a..
Solutions for Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a. in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a. defined & explained in the simplest way possible. Besides giving the explanation of
Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a., a detailed solution for Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a. has been provided alongside types of Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a. theory, EduRev gives you an
ample number of questions to practice Can you explain the answer of this question below:A carnot engine is taking 700 cal from source and is rejecting 500 cal to the sink in each cycle. What is the temperature of sink if the source temperature is 150° C .A:29.02° CB:27.75° CC:30.05° CD:31.5° CThe answer is a. tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup on EduRev and stay on top of your study goals
10M+ students crushing their study goals daily