Can you explain the answer of this question below:A Carnot cycle refri...
COP = T2/ (T1 – T2)= 250/300-250= 5.The answer is b.
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Can you explain the answer of this question below:A Carnot cycle refri...
Coefficient of Performance (COP) is a measure of the efficiency of a refrigeration system. It is defined as the ratio of the amount of heat extracted from the cold reservoir to the amount of work done by the system. The Carnot cycle is an idealized thermodynamic cycle that describes the most efficient heat engine possible.
The Carnot Cycle
The Carnot cycle consists of four reversible processes: isothermal expansion, adiabatic expansion, isothermal compression, and adiabatic compression. In a Carnot refrigerator, the roles of heat input and heat output are reversed compared to a heat engine. The Carnot cycle refrigerator operates by extracting heat from a cold reservoir and rejecting it to a hot reservoir.
Given Information
The Carnot cycle refrigerator operates between a low temperature, T_low = 250K, and a high temperature, T_high = 300K.
Finding the Coefficient of Performance (COP)
The COP of a Carnot cycle refrigerator can be determined using the formula:
COP = T_low / (T_high - T_low)
Substituting the given values:
COP = 250 / (300 - 250)
COP = 250 / 50
COP = 5.0
Conclusion
Therefore, the coefficient of performance (COP) of the Carnot cycle refrigerator operating between 250K and 300K is 5.0, which means that for every unit of work input, it can extract 5 units of heat from the cold reservoir. Hence, the correct answer is option B: 5.0.
Can you explain the answer of this question below:A Carnot cycle refri...
Option A
Given ,
T1 = 250K
T2 = 300K
=> COP of Refrigerator = T2 / ( T1 - T2 )
=> 300 / ( 300 - 250 )
=> 6.0 .. So , COP of Refrigerator = 6.0