Can you explain the answer of this question below:The atomic numbers of vanadium (V). Chromium (Cr), manganese (Mn) and iron (Fe) respectively 23, 24, 25 and 26. Which one of these may be expected to have the higher second ionization enthalpy ? [AIEEE-2003]A:CrB:MnC:FeD:VThe answer is A.

Question

Can you explain the answer of this question below:The atomic numbers of vanadium (V). Chromium (Cr), manganese (Mn) and iron (Fe) respectively 23, 24, 25 and 26. Which one of these may be expected to have the higher second ionization enthalpy ?          [AIEEE-2003]A:CrB:MnC:FeD:VThe answer is A.

Answer

The electronic configuration of Cr is 1s2 2s2 2p6 3s2 3p6 3d5 4s1 one electron from 4s orbital goes to 3d orbital to attain more stability. thus for first ionization enthalpy one electron from 4s orbital will be removed. For second ionization enthalpy one electron will be removed from 3d orbital. as it has 5 electrons ( half filled orbital has more stability ) more energy is required to remove one electron from stable orbital.

Answer

The electronic configurations are as follows;

V:(Ar)3d³4s²

Cr:(Ar)3d⁵4s¹

Mn:(Ar)3d⁵4s²

Fe:(Ar)3d⁶4s²

The second ionization of Cr means removal of electron from the stable configuration of 3d⁵.

The highest second ionization enthalpy is Cr

Hence a is the correct answer.

Answer

B

Answer

Explanation:

Atomic Numbers:
- Vanadium (V): 23
- Chromium (Cr): 24
- Manganese (Mn): 25
- Iron (Fe): 26

Second Ionization Enthalpy:
- The second ionization enthalpy is the energy required to remove a second electron from a singly charged ion.
- It is generally higher than the first ionization enthalpy as the removal of a second electron involves removing an electron from a positively charged ion, which requires more energy.

Relation to Atomic Number:
- As we move across a period in the periodic table from left to right, the atomic number increases.
- The atomic number is directly proportional to the number of protons in the nucleus, which determines the strength of attraction between the nucleus and the electrons.

Explanation of Answer:
- Chromium (Cr) has an atomic number of 24, which is higher than Vanadium (V) with an atomic number of 23.
- Since the atomic number of Chromium is higher than Vanadium, the effective nuclear charge experienced by the electrons in Chromium is greater.
- This stronger nuclear charge in Chromium makes it more difficult to remove a second electron compared to Vanadium.
- Therefore, Chromium (Cr) may be expected to have the higher second ionization enthalpy among the given elements.
Therefore, the correct answer is A: Cr.

Top Courses for Class 11View all

Chemistry Class 11

CUET Mock Test Series

English Class 11

Chemistry Practice Tests: CUET Preparation

CUET Mock Test: Humanities Subjects 2025

Top Courses for Class 11

Top Courses for Class 11

Suggested Free Tests

Related Content

Schools

Competitive Examinations

Quick Access Links

Technical Exams