Mohan can do a bit of work in 25 days which can be completed by Sohan ...
Given:
Part of the work done by Mohan in 25 days = Part of the work done by Sohan in 20 days
Formula Used:
Work done = Time × Efficiency
Calculation:
Let the total work done by Mohan in 25 days = x units
So, Mohan's efficiency = x/25
Also, Sohan's efficiency = x/20
Hence, the part of the work they complete together in 5 days:
5 × [(x/25) + (x/20)] = 9x/20
Remaining work = x - (9x/20) = 11x/20
∴ Time taken by Sohan to complete the remaining work = (11x/20)/(x/20) = 11 days
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Mohan can do a bit of work in 25 days which can be completed by Sohan ...
Let's assume that Mohan's work rate is M units per day and Sohan's work rate is S units per day.
According to the given information:
Mohan can do a bit of work in 25 days, which means he can complete 1/25th of the work in a day.
So, Mohan's work rate (M) = 1/25 units/day.
Sohan can do the same bit of work in 20 days, which means he can complete 1/20th of the work in a day.
So, Sohan's work rate (S) = 1/20 units/day.
Working together for 5 days:
When Mohan and Sohan work together for 5 days, their combined work rate is the sum of their individual work rates.
Total work done in 5 days = (M + S) * 5
Remaining work:
The total work is completed by Mohan and Sohan in 25 days, and they worked together for 5 days. So, the remaining work is:
Remaining work = Total work - Work done in 5 days
Remaining work = 1 - (M + S) * 5
Time taken by Sohan to complete the remaining work:
Now, we need to find out how long Sohan will take to complete the remaining work. Let's assume it will take Sohan T days to complete the remaining work.
So, Sohan's work rate (S) = Remaining work / T
1/20 = [1 - (M + S) * 5] / T
Solving the equation:
Let's substitute the values of M and S and solve the equation to find the value of T.
1/20 = [1 - (1/25 + 1/20) * 5] / T
1/20 = [1 - (9/100)] / T
1/20 = (91/100) / T
T = (100 * 20) / 91
T ≈ 21
Hence, Sohan will take approximately 21 days to complete the remaining work.
Therefore, the correct answer is option (d) 21 days.