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Can you explain the answer of this question below:
In a Darlington pair configuration, if emitter resistance is 560Ω and input resistance is 8.75MΩ than AC current gain will be
  • A:
    25
  • B:
    125
  • C:
    321
  • D:
    345
The answer is b.
Most Upvoted Answer
Can you explain the answer of this question below:In a Darlington pair...
Ohms and base current is 20 mA, calculate the collector current.

Assuming the Darlington pair is in active mode, the collector current can be calculated using the formula:

Ic = β * Ib

Where Ic is the collector current, Ib is the base current, and β is the current gain of the transistor.

In a Darlington pair configuration, the current gain is the product of the current gains of the two transistors. Since the two transistors are connected in series, their current gains multiply together.

For example, if the current gain of each transistor is 100, the current gain of the Darlington pair is:

β = β1 * β2 = 100 * 100 = 10,000

Therefore, the collector current is:

Ic = β * Ib = 10,000 * 20 mA = 200 mA

So the collector current is 200 mA. Note that this calculation assumes ideal transistors with infinite current gain. In reality, the current gain is limited and may be lower than the calculated value.
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Community Answer
Can you explain the answer of this question below:In a Darlington pair...
D
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Can you explain the answer of this question below:In a Darlington pair configuration, if emitter resistance is 560Ω and input resistance is 8.75MΩ than AC current gain will beA:25B:125C:321D:345The answer is b.
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