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A solution containing 2.5 × 10-3 kg of a solute dissolved in 75 × 10-3 kg of water boils at 373.535 K. The molar mass of the solute is _________ g mol-1. [Nearest integer] (Given: Kb (H2O) = 0.52 K Kg mol-1, boiling point of water = 373.15 K)
Correct answer is '45'. Can you explain this answer?
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A solution containing 2.5 × 10-3kg of a solute dissolved in 75 &...
Given Data:
- Mass of solute = 2.5 × 10^-3 kg
- Mass of water = 75 × 10^-3 kg
- Boiling point of solution = 373.535 K
- Kb(H2O) = 0.52 K kg mol^-1
- Boiling point of water = 373.15 K
Calculating Molality:
Molality (m) = moles of solute / mass of solvent (in kg)
Moles of solute = mass of solute / molar mass of solute
Mass of solvent = mass of water
Given that the boiling point of the solution is 373.535 K, and the boiling point elevation (ΔTb) is:
ΔTb = Tb(solution) - Tb(solvent)
ΔTb = 373.535 K - 373.15 K = 0.385 K
Using the formula for boiling point elevation:
ΔTb = Kb * m
0.385 K = 0.52 K kg mol^-1 * m
m = 0.385 K / 0.52 K kg mol^-1 = 0.7404 mol kg^-1
Now, we can calculate the moles of solute:
m = moles of solute / 0.075 kg
0.7404 mol kg^-1 = moles of solute / 0.075 kg
moles of solute = 0.7404 mol kg^-1 * 0.075 kg = 0.05553 mol
Calculating Molar Mass:
Molar mass of solute = mass of solute / moles of solute
Molar mass of solute = 2.5 × 10^-3 kg / 0.05553 mol = 45 g mol^-1
Therefore, the molar mass of the solute is 45 g mol^-1.
- Mass of solute = 2.5 × 10^-3 kg
- Mass of water = 75 × 10^-3 kg
- Boiling point of solution = 373.535 K
- Kb(H2O) = 0.52 K kg mol^-1
- Boiling point of water = 373.15 K
Calculating Molality:
Molality (m) = moles of solute / mass of solvent (in kg)
Moles of solute = mass of solute / molar mass of solute
Mass of solvent = mass of water
Given that the boiling point of the solution is 373.535 K, and the boiling point elevation (ΔTb) is:
ΔTb = Tb(solution) - Tb(solvent)
ΔTb = 373.535 K - 373.15 K = 0.385 K
Using the formula for boiling point elevation:
ΔTb = Kb * m
0.385 K = 0.52 K kg mol^-1 * m
m = 0.385 K / 0.52 K kg mol^-1 = 0.7404 mol kg^-1
Now, we can calculate the moles of solute:
m = moles of solute / 0.075 kg
0.7404 mol kg^-1 = moles of solute / 0.075 kg
moles of solute = 0.7404 mol kg^-1 * 0.075 kg = 0.05553 mol
Calculating Molar Mass:
Molar mass of solute = mass of solute / moles of solute
Molar mass of solute = 2.5 × 10^-3 kg / 0.05553 mol = 45 g mol^-1
Therefore, the molar mass of the solute is 45 g mol^-1.
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A solution containing 2.5 × 10-3kg of a solute dissolved in 75 × 10-3kg of water boils at 373.535 K. The molar mass of the solute is _________ g mol-1. [Nearest integer] (Given: Kb(H2O) = 0.52 K Kg mol-1, boiling point of water = 373.15 K)Correct answer is '45'. Can you explain this answer?
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A solution containing 2.5 × 10-3kg of a solute dissolved in 75 × 10-3kg of water boils at 373.535 K. The molar mass of the solute is _________ g mol-1. [Nearest integer] (Given: Kb(H2O) = 0.52 K Kg mol-1, boiling point of water = 373.15 K)Correct answer is '45'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solution containing 2.5 × 10-3kg of a solute dissolved in 75 × 10-3kg of water boils at 373.535 K. The molar mass of the solute is _________ g mol-1. [Nearest integer] (Given: Kb(H2O) = 0.52 K Kg mol-1, boiling point of water = 373.15 K)Correct answer is '45'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution containing 2.5 × 10-3kg of a solute dissolved in 75 × 10-3kg of water boils at 373.535 K. The molar mass of the solute is _________ g mol-1. [Nearest integer] (Given: Kb(H2O) = 0.52 K Kg mol-1, boiling point of water = 373.15 K)Correct answer is '45'. Can you explain this answer?.
A solution containing 2.5 × 10-3kg of a solute dissolved in 75 × 10-3kg of water boils at 373.535 K. The molar mass of the solute is _________ g mol-1. [Nearest integer] (Given: Kb(H2O) = 0.52 K Kg mol-1, boiling point of water = 373.15 K)Correct answer is '45'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solution containing 2.5 × 10-3kg of a solute dissolved in 75 × 10-3kg of water boils at 373.535 K. The molar mass of the solute is _________ g mol-1. [Nearest integer] (Given: Kb(H2O) = 0.52 K Kg mol-1, boiling point of water = 373.15 K)Correct answer is '45'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution containing 2.5 × 10-3kg of a solute dissolved in 75 × 10-3kg of water boils at 373.535 K. The molar mass of the solute is _________ g mol-1. [Nearest integer] (Given: Kb(H2O) = 0.52 K Kg mol-1, boiling point of water = 373.15 K)Correct answer is '45'. Can you explain this answer?.
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