Can you explain the answer of this question below:The quantity of a ch...
We know that, I=Q/t or Q=I x t= 10x1 hours
{since unit of current is Cs-1, therefore time should be in seconds}
Therefore, Q=10x60x60=36000=3.6x104 C
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Can you explain the answer of this question below:The quantity of a ch...
Since, we know that i=q/t or q=i×t here i=10 A, t= 1 hour=60×60=3600 sec So, charge(q)=i×t=10×3600=3.6×10^4 C
Can you explain the answer of this question below:The quantity of a ch...
Question: The quantity of a charge that will be transferred by a current flow of 10 A over a 1-hour period is _________?
Answer: The correct answer is B: 3.6 x 10^4 C.
Explanation:
Understanding the Problem:
To solve this problem, we need to understand the relationship between current, time, and charge. The flow of electric charge is measured in coulombs (C), and the current is the rate at which charge flows. Therefore, to find the quantity of charge transferred, we need to multiply the current by the time for which it flows.
Calculating the Charge:
Given:
- Current (I) = 10 A
- Time (t) = 1 hour
To calculate the charge transferred, we use the formula:
Q = I * t
where Q is the charge, I is the current, and t is the time.
Substituting the given values:
Q = 10 A * 1 hour
Converting Time to Seconds:
To calculate charge, it is essential to use the SI unit of time, which is seconds. Therefore, we need to convert the time from hours to seconds.
1 hour is equal to 60 minutes, and 1 minute is equal to 60 seconds. So, 1 hour is equal to 60 * 60 = 3600 seconds.
Q = 10 A * 3600 seconds
Calculating the Charge:
Now, let's calculate the charge.
Q = 10 A * 3600 seconds
Q = 36000 C
Therefore, the quantity of charge transferred by a current flow of 10 A over a 1-hour period is 36000 C, which can be written as 3.6 x 10^4 C.
Final Answer:
The correct answer is B: 3.6 x 10^4 C.