To find the ratio of masses of H2SO4 and Al2(SO4)3, we need to determine the molar masses of both compounds and then compare the number of moles of sulfur in each compound.

1. Calculate the molar mass of H2SO4:
- Hydrogen (H) has a molar mass of 1 g/mol, so 2 hydrogen atoms contribute (2 x 1) = 2 g/mol.
- Sulfur (S) has a molar mass of 32 g/mol.
- Oxygen (O) has a molar mass of 16 g/mol, so 4 oxygen atoms contribute (4 x 16) = 64 g/mol.
- Adding up the contributions, we get: 2 + 32 + 64 = 98 g/mol.

2. Calculate the molar mass of Al2(SO4)3:
- Aluminum (Al) has a molar mass of 27 g/mol, so 2 aluminum atoms contribute (2 x 27) = 54 g/mol.
- Sulfur (S) has a molar mass of 32 g/mol, so 3 sulfur atoms contribute (3 x 32) = 96 g/mol.
- Oxygen (O) has a molar mass of 16 g/mol, so 12 oxygen atoms contribute (12 x 16) = 192 g/mol.
- Adding up the contributions, we get: 54 + 96 + 192 = 342 g/mol.

3. Determine the number of moles of S in each compound:
- For H2SO4, the molar mass of sulfur is 32 g/mol and the total molar mass of the compound is 98 g/mol. Therefore, the number of moles of S in H2SO4 is (32/98) = 0.326 moles.
- For Al2(SO4)3, the molar mass of sulfur is 32 g/mol and the total molar mass of the compound is 342 g/mol. Therefore, the number of moles of S in Al2(SO4)3 is (32/342) = 0.094 moles.

4. Find the ratio of masses of H2SO4 and Al2(SO4)3:
- Divide the number of moles of S in H2SO4 by the number of moles of S in Al2(SO4)3: (0.326/0.094) = 3.468.
- Since the ratio is asking for the mass ratio, multiply the ratio by the molar mass of sulfur: 3.468 x 32 = 111.096.
- Round the answer to two decimal places: 111.10.

Therefore, the ratio of masses of H2SO4 and Al2(SO4)3, both containing 32 grams of S, is approximately 111.10. However, none of the given options match this answer.