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Can you explain the answer of this question below:
sp3-hybridisation is found in
  • A:
    [ZnCI4]2-
  • B:
    [Cu(NH3)4]2+
  • C:
    [CuCI4]2-
  • D:
    [Ni(CO)4]
The answer is A,C,D.
Most Upvoted Answer
Can you explain the answer of this question below:sp3-hybridisation is...
Explanation:

SP3 hybridization is a type of hybridization where one s orbital and three p orbitals of the same shell of an atom mix to form four sp3 hybrid orbitals. These hybrid orbitals are arranged in a tetrahedral shape around the central atom.

The given options are:

a) [ZnCl4]2-
b) [Cu(NH3)4]2
c) [CuCl4]2-
d) [Ni(CO)4]

a) [ZnCl4]2-: In this complex ion, the central zinc atom is sp3 hybridized. The zinc ion has an electronic configuration of [Ar]3d104s0. The hybridization of the zinc ion takes place by mixing one 4s orbital and three 4p orbitals to form four sp3 hybrid orbitals.

b) [Cu(NH3)4]2: In this complex ion, the central copper atom is dsp2 hybridized. The copper ion has an electronic configuration of [Ar]3d104s1. The hybridization of the copper ion takes place by mixing one 4s orbital, two 4p orbitals, and one 3d orbital to form five dsp2 hybrid orbitals.

c) [CuCl4]2-: In this complex ion, the central copper atom is sp3 hybridized. The copper ion has an electronic configuration of [Ar]3d104s1. The hybridization of the copper ion takes place by mixing one 4s orbital and three 4p orbitals to form four sp3 hybrid orbitals.

d) [Ni(CO)4]: In this complex ion, the central nickel atom is sp3 hybridized. The nickel ion has an electronic configuration of [Ar]3d84s2. The hybridization of the nickel ion takes place by mixing one 4s orbital and three 4p orbitals to form four sp3 hybrid orbitals.

Conclusion:

Thus, the correct options are A, C, and D, as all these complex ions have a central atom that is sp3 hybridized. The complex ion in option B has a central copper atom that is dsp2 hybridized.
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Community Answer
Can you explain the answer of this question below:sp3-hybridisation is...
Correct answer are A,C,Din option a Zn had +2 chargeIn option c Cu also has +2 charge but halogen are weak filled ligand so it has sp³ hybridizationIn option d In has 0 charge so its s orbital become empty and it has 0 unpaired electron that's why it has also sp³ hybridization
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Can you explain the answer of this question below:sp3-hybridisation is found inA:[ZnCI4]2-B:[Cu(NH3)4]2+C:[CuCI4]2-D:[Ni(CO)4]The answer is A,C,D.
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