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The ratio of the quantities is 5:7 . If the consequent of its inverse ration is 5, the antecedent is?
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The ratio of the quantities is 5:7 . If the consequent of its inverse ...
The given ratio is 5:7.

The given ratio is 5:7, which means that for every 5 units of one quantity, there are 7 units of another quantity. Let's assume that the first quantity is represented by x and the second quantity is represented by y.

The inverse ratio of 5:7 is 7:5.

To find the inverse ratio, we simply interchange the antecedent and consequent of the given ratio. Therefore, the inverse ratio of 5:7 is 7:5.

The consequent of the inverse ratio is 5.

It is given that the consequent of the inverse ratio is 5. In the inverse ratio 7:5, the consequent is 5. Let's assume that the antecedent of the inverse ratio is represented by a.

Using the concept of proportions, we can set up the following equation:

Since the inverse ratio is 7:5, we can set up the proportion as follows:

7/5 = a/5

Solving the proportion:

To solve the proportion, we cross-multiply and solve for a:

7 * 5 = 5 * a

35 = 5a

Dividing both sides of the equation by 5, we get:

35/5 = a

7 = a

Therefore, the antecedent of the inverse ratio is 7.

The antecedent of the inverse ratio is 7.

After solving the proportion, we find that the antecedent of the inverse ratio is 7.
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The ratio of the quantities is 5:7 . If the consequent of its inverse ration is 5, the antecedent is?
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