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Can you explain the answer of this question below:
Radiation of λ = 155 nm was irradiated on Li (work function = 5eV) plate. The stopping potential (in eV) is.
- A:3eV
- B:4eV
- C:0.3eV
- D:0.5 eV
The answer is a.
Verified Answer
Can you explain the answer of this question below:Radiation of λ ...
K.E.= hv − hv0 = hc/λ − W.F.= 6.6 x 10^−34 x 3 x 10^8/λ − 5 x 1.6 x 10^−19 and
K.Emax = eV0 where V0 is stopping potential so
V0 = 3eV
Most Upvoted Answer
Can you explain the answer of this question below:Radiation of λ ...
Ypp it's right E = KE - stoping potential. E = 1240evÅ/155Å. KE = qV stopping potential = 5eV put the value in the equation nd u will find ur ans
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Can you explain the answer of this question below:Radiation of λ ...
Understanding the Photoelectric Effect
The photoelectric effect occurs when light of sufficient energy strikes a material, causing the ejection of electrons. The energy of the incoming light can be calculated using the formula:
Energy (E) = hc / λ
where:
- h = Planck's constant (4.1357 x 10^-15 eV·s)
- c = speed of light (3 x 10^8 m/s)
- λ = wavelength of light (in meters)
Calculating Energy from Wavelength
- Given:
- λ = 155 nm = 155 x 10^-9 m
- Substituting values:
- E = (4.1357 x 10^-15 eV·s) * (3 x 10^8 m/s) / (155 x 10^-9 m)
- E = approximately 8.06 eV
Comparing with Work Function
- Work function of Li = 5 eV
- The excess energy that can be converted into kinetic energy of the emitted electrons is given by:
Kinetic Energy (KE) = E - Work Function
- KE = 8.06 eV - 5 eV
- KE = 3.06 eV
Stoppage Potential
- The stopping potential (V) is equal to the maximum kinetic energy of the emitted electrons in eV.
- Therefore, V = KE = 3.06 eV.
Thus, the stopping potential is approximately 3 eV.
Conclusion
The correct answer is A: 3 eV. This result demonstrates the relationship between light energy, work function, and the kinetic energy of emitted electrons in the context of the photoelectric effect.
The photoelectric effect occurs when light of sufficient energy strikes a material, causing the ejection of electrons. The energy of the incoming light can be calculated using the formula:
Energy (E) = hc / λ
where:
- h = Planck's constant (4.1357 x 10^-15 eV·s)
- c = speed of light (3 x 10^8 m/s)
- λ = wavelength of light (in meters)
Calculating Energy from Wavelength
- Given:
- λ = 155 nm = 155 x 10^-9 m
- Substituting values:
- E = (4.1357 x 10^-15 eV·s) * (3 x 10^8 m/s) / (155 x 10^-9 m)
- E = approximately 8.06 eV
Comparing with Work Function
- Work function of Li = 5 eV
- The excess energy that can be converted into kinetic energy of the emitted electrons is given by:
Kinetic Energy (KE) = E - Work Function
- KE = 8.06 eV - 5 eV
- KE = 3.06 eV
Stoppage Potential
- The stopping potential (V) is equal to the maximum kinetic energy of the emitted electrons in eV.
- Therefore, V = KE = 3.06 eV.
Thus, the stopping potential is approximately 3 eV.
Conclusion
The correct answer is A: 3 eV. This result demonstrates the relationship between light energy, work function, and the kinetic energy of emitted electrons in the context of the photoelectric effect.
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Can you explain the answer of this question below:Radiation of λ = 155 nm was irradiated on Li (work function = 5eV) plate. The stopping potential (in eV) is.A:3eVB:4eVC:0.3eVD:0.5 eVThe answer is a. for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Can you explain the answer of this question below:Radiation of λ = 155 nm was irradiated on Li (work function = 5eV) plate. The stopping potential (in eV) is.A:3eVB:4eVC:0.3eVD:0.5 eVThe answer is a. covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you explain the answer of this question below:Radiation of λ = 155 nm was irradiated on Li (work function = 5eV) plate. The stopping potential (in eV) is.A:3eVB:4eVC:0.3eVD:0.5 eVThe answer is a..
Can you explain the answer of this question below:Radiation of λ = 155 nm was irradiated on Li (work function = 5eV) plate. The stopping potential (in eV) is.A:3eVB:4eVC:0.3eVD:0.5 eVThe answer is a. for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Can you explain the answer of this question below:Radiation of λ = 155 nm was irradiated on Li (work function = 5eV) plate. The stopping potential (in eV) is.A:3eVB:4eVC:0.3eVD:0.5 eVThe answer is a. covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you explain the answer of this question below:Radiation of λ = 155 nm was irradiated on Li (work function = 5eV) plate. The stopping potential (in eV) is.A:3eVB:4eVC:0.3eVD:0.5 eVThe answer is a..
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