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In a university club of 200 people, the number of Political Science majors is 50 less than 4 times the number of International Relations majors. If one fifth of the club members are neither Political Science majors nor International Relations majors, and no club member is majoring in both Political Science and International Relations, how many of the club members are International Relations majors?
  • a)
    42
  • b)
    50
  • c)
    71
  • d)
    95
  • e)
    124
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In a university club of 200 people, the number of Political Science ma...
The correct response is (A). Let P be the number of Political Science majors and let R be the number of International Relations majors. "One fifth of the legislators are neither," so there are 1/5 *200 = 40 legislators who are neither. Hence, there are 200 – 40 = 160 Poly-Sci majors and IR majors, or P + R = 160. Translating the clause "the number of Poly-Sci majors is 50 less than 4 times the number of IR majors" into an equation yields P = 4R – 50.
Plugging this into the equation P + R = 160 yields:
4R – 50 + R = 160
5R – 50 = 160
5R = 210
R = 42
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Most Upvoted Answer
In a university club of 200 people, the number of Political Science ma...
Understanding the Problem
In the university club of 200 members, we need to find the number of International Relations majors given the relationship between the Political Science and International Relations majors.
Defining Variables
- Let x = number of International Relations majors.
- Then, the number of Political Science majors = 4x - 50.
Calculating Members in Each Major
Since one fifth of the club members are neither majors, we can determine that:
- Members neither in Political Science nor International Relations = 1/5 of 200 = 40.
Thus, the total number of members who are either Political Science or International Relations majors is:
- Total majors = 200 - 40 = 160.
Setting Up the Equation
Now, we can set up the equation based on the majors:
- Total members in majors = Political Science majors + International Relations majors
- 160 = (4x - 50) + x.
This simplifies to:
- 160 = 5x - 50.
Simplifying the Equation
Now, adding 50 to both sides gives:
- 210 = 5x.
Dividing both sides by 5, we find:
- x = 42.
Conclusion
Thus, the number of International Relations majors is 42, which corresponds to option 'A'.
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In a university club of 200 people, the number of Political Science majors is 50 less than 4 times the number of International Relations majors. If one fifth of the club members are neither Political Science majors nor International Relations majors, and no club member is majoring in both Political Science and International Relations, how many of the club members are International Relations majors?a)42b)50c)71d)95e)124Correct answer is option 'A'. Can you explain this answer? for GMAT 2025 is part of GMAT preparation. The Question and answers have been prepared according to the GMAT exam syllabus. Information about In a university club of 200 people, the number of Political Science majors is 50 less than 4 times the number of International Relations majors. If one fifth of the club members are neither Political Science majors nor International Relations majors, and no club member is majoring in both Political Science and International Relations, how many of the club members are International Relations majors?a)42b)50c)71d)95e)124Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for GMAT 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In a university club of 200 people, the number of Political Science majors is 50 less than 4 times the number of International Relations majors. If one fifth of the club members are neither Political Science majors nor International Relations majors, and no club member is majoring in both Political Science and International Relations, how many of the club members are International Relations majors?a)42b)50c)71d)95e)124Correct answer is option 'A'. Can you explain this answer?.
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