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Can you explain the answer of this question below:
If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:
- A:+ 1412 KJ mol–1
- B:– 1412 KJ mol–1
- C:+ 141.2 KJ mol–1
- D:– 141.2 KJ mol–1
The answer is b.
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The chemical equation for the above reaction is:
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Enthalpy of Formation:
The enthalpy of formation (∆Hf) is the enthalpy change that occurs when one mole of a substance is formed from its elements in their standard states under standard conditions. The enthalpy of formation values for C2H4 (g), CO2 (g), and H2O (l) at 2500C and 1 atm. pressure are given as 52, 394, and 286 KJ mol1 respectively.
Enthalpy of Combustion:
The enthalpy of combustion (∆Hc) is the enthalpy change that occurs when one mole of a substance is completely burned in excess oxygen under standard conditions. In this case, we are looking for the enthalpy of combustion of C2H4 (g).
Using the enthalpy of formation values, we can calculate the enthalpy of combustion using the following equation:
∆Hc = ∑(∆Hf products) - ∑(∆Hf reactants)
Where:
∆Hc is the enthalpy of combustion
∆Hf products is the sum of the enthalpies of formation of the products
∆Hf reactants is the sum of the enthalpies of formation of the reactants
Calculating the Enthalpy of Combustion:
In this case, the reactant is C2H4 (g) and the products are CO2 (g) and H2O (l). Using the given enthalpy of formation values, we can calculate the enthalpy of combustion as follows:
∆Hc = (∆Hf CO2) + (∆Hf H2O) - (∆Hf C2H4)
∆Hc = (394 KJ mol1) + (286 KJ mol1) - (52 KJ mol1)
∆Hc = 628 KJ mol1 - 52 KJ mol1
∆Hc = 576 KJ mol1
Therefore, the enthalpy of combustion of C2H4 (g) is 576 KJ mol1.
Answer:
According to the options given, the correct answer is B: 1412 KJ mol1. However, this answer does not match with the calculated value of 576 KJ mol1. Therefore, the given answer appears to be incorrect.
Please note that the provided answer does not match with the calculated value.
The enthalpy of formation (∆Hf) is the enthalpy change that occurs when one mole of a substance is formed from its elements in their standard states under standard conditions. The enthalpy of formation values for C2H4 (g), CO2 (g), and H2O (l) at 2500C and 1 atm. pressure are given as 52, 394, and 286 KJ mol1 respectively.
Enthalpy of Combustion:
The enthalpy of combustion (∆Hc) is the enthalpy change that occurs when one mole of a substance is completely burned in excess oxygen under standard conditions. In this case, we are looking for the enthalpy of combustion of C2H4 (g).
Using the enthalpy of formation values, we can calculate the enthalpy of combustion using the following equation:
∆Hc = ∑(∆Hf products) - ∑(∆Hf reactants)
Where:
∆Hc is the enthalpy of combustion
∆Hf products is the sum of the enthalpies of formation of the products
∆Hf reactants is the sum of the enthalpies of formation of the reactants
Calculating the Enthalpy of Combustion:
In this case, the reactant is C2H4 (g) and the products are CO2 (g) and H2O (l). Using the given enthalpy of formation values, we can calculate the enthalpy of combustion as follows:
∆Hc = (∆Hf CO2) + (∆Hf H2O) - (∆Hf C2H4)
∆Hc = (394 KJ mol1) + (286 KJ mol1) - (52 KJ mol1)
∆Hc = 628 KJ mol1 - 52 KJ mol1
∆Hc = 576 KJ mol1
Therefore, the enthalpy of combustion of C2H4 (g) is 576 KJ mol1.
Answer:
According to the options given, the correct answer is B: 1412 KJ mol1. However, this answer does not match with the calculated value of 576 KJ mol1. Therefore, the given answer appears to be incorrect.
Please note that the provided answer does not match with the calculated value.
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Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b.
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Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b. for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b. covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b..
Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b. for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b. covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b..
Solutions for Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b. in English & in Hindi are available as part of our courses for Chemistry.
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Here you can find the meaning of Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b. defined & explained in the simplest way possible. Besides giving the explanation of
Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b., a detailed solution for Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b. has been provided alongside types of Can you explain the answer of this question below:If enthalpies of formation C2H4 (g), CO2 (g) and H2O (l) at 2500C and 1 atm. pressure be 52, –394 and –286 KJ mol–1 respectively. The enthalpy of combustion of C2H4 (g) will be:A:+ 1412 KJ mol–1B:– 1412 KJ mol–1C:+ 141.2 KJ mol–1D:– 141.2 KJ mol–1The answer is b. theory, EduRev gives you an
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