Can you explain the answer of this question below:How many atoms of Oxygen are there in 18g of water? (Hint: Avagadro’s Number = 6.02 x1023atoms/mol)a:8.02 x1023b:6.02 x1023c:5 .02 x1023d:7.02 x1023Correct answer is 'b'.

Question

Can you explain the answer of this question below:How many atoms of Oxygen are there in 18g of water? (Hint: Avagadro&#8217;s Number = 6.02 x1023atoms/mol)a:8.02 x1023b:6.02 x1023c:5 .02 x1023d:7.02 x1023Correct answer is 'b'.

Answer

Number of molecules of H2O =18*6.02*10^23/18 =6.02*10^23 ...... then , there are 1 O atom in H2O ...so , number of O atoms in 18 gm of H2O = 6.02 *10^23.....

Answer

's number is 6.022 x 10^23)

To solve this problem, we need to know the molecular formula of water, which is H2O. This means that each water molecule contains 2 hydrogen atoms and 1 oxygen atom.

To calculate the number of oxygen atoms in 18g of water, we first need to determine how many moles of water are present. We can use the formula:

moles = mass / molar mass

The molar mass of water is 18 g/mol (2 x 1.008 g/mol for hydrogen + 1 x 16.00 g/mol for oxygen). Therefore:

moles of water = 18 g / 18 g/mol = 1 mol

Since each mole of water contains 1 mole of oxygen atoms, we can use Avogadro's number to determine the number of atoms:

number of oxygen atoms = 1 mol x 6.022 x 10^23 atoms/mol = 6.022 x 10^23 atoms

Therefore, there are 6.022 x 10^23 atoms of oxygen in 18g of water.

Answer

One mole of any molecule contain 6.023×10^23 atoms..

Answer

There is one mole of water in 18 gram and in one mole of h2o one mole of oxygen is present therefore no. of atoms of oxygen in h2o is equal to avagadro constant i.e. 6.02× 10²³.

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