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If in a shift resistor Q0 is fed back to input the resulting counter is
- a)Twisted ring with N : 1 scale
- b)Ring counter with N : 1 scale
- c)Twisted ring with 2 N : 1 scale
- d)Ring counter with 2 N : 1 scale
Correct answer is option 'C'. Can you explain this answer?
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If in a shift resistor Q0 is fed back to input the resulting counter i...
Answer:
In a shift resistor, when Q0 is fed back to the input, the resulting counter is a twisted ring counter with a scale of 2N:1.
Explanation:
A shift register is a type of digital circuit that is capable of shifting its data bits one position at a time. It can be used to create a variety of digital circuits, including counters. A shift register counter is a sequential circuit that can count in a specific sequence by shifting the bits through the register.
In a ring counter, the output of the last stage is fed back to the input of the first stage, creating a loop. This allows the bits to circulate through the counter, creating a counting sequence. However, in a regular ring counter, the scale of the counter is N:1, where N is the number of stages or bits in the counter.
When Q0 is fed back to the input of a shift register counter, it creates a twisted ring counter. This means that the output of the first stage is not directly connected to the input of the first stage, but is instead connected to the input of a different stage, creating a twist in the loop. This twist in the loop changes the scale of the counter.
Example:
Let's consider a 4-bit shift register counter. In a regular ring counter, the scale would be 4:1, meaning that it would take four clock cycles for the counter to complete a full cycle. However, when Q0 is fed back to the input, the resulting twisted ring counter has a scale of 2N:1, which in this case is 8:1.
This means that it would take eight clock cycles for the counter to complete a full cycle. The feedback from Q0 to the input effectively doubles the length of the counter sequence.
Therefore, the correct answer is option C - a twisted ring counter with a scale of 2N:1.
In a shift resistor, when Q0 is fed back to the input, the resulting counter is a twisted ring counter with a scale of 2N:1.
Explanation:
A shift register is a type of digital circuit that is capable of shifting its data bits one position at a time. It can be used to create a variety of digital circuits, including counters. A shift register counter is a sequential circuit that can count in a specific sequence by shifting the bits through the register.
In a ring counter, the output of the last stage is fed back to the input of the first stage, creating a loop. This allows the bits to circulate through the counter, creating a counting sequence. However, in a regular ring counter, the scale of the counter is N:1, where N is the number of stages or bits in the counter.
When Q0 is fed back to the input of a shift register counter, it creates a twisted ring counter. This means that the output of the first stage is not directly connected to the input of the first stage, but is instead connected to the input of a different stage, creating a twist in the loop. This twist in the loop changes the scale of the counter.
Example:
Let's consider a 4-bit shift register counter. In a regular ring counter, the scale would be 4:1, meaning that it would take four clock cycles for the counter to complete a full cycle. However, when Q0 is fed back to the input, the resulting twisted ring counter has a scale of 2N:1, which in this case is 8:1.
This means that it would take eight clock cycles for the counter to complete a full cycle. The feedback from Q0 to the input effectively doubles the length of the counter sequence.
Therefore, the correct answer is option C - a twisted ring counter with a scale of 2N:1.
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If in a shift resistor Q0 is fed back to input the resulting counter isa)Twisted ring with N : 1 scaleb)Ring counter with N : 1 scalec)Twisted ring with 2 N : 1 scaled)Ring counter with 2 N : 1 scaleCorrect answer is option 'C'. Can you explain this answer?
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