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Suppose that it takes 1 unit of time to transmit a packet (of fixed size) on a communication link. The link layer uses a window flow control protocol with a window size of N packets. Each packet causes an ack or a nak to be generated by the receiver, and ack/nak transmission times are negligible. Further, the round trip time on the link is equal to N units. Consider time i > N. If only acks have been received till time i(no naks), then the goodput evaluated at the transmitter at time i (in packets per unit time) isa)1 - N/ib)i/(N + i)c)1d)1 - e(i/N)Correct answer is 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared
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the Computer Science Engineering (CSE) exam syllabus. Information about Suppose that it takes 1 unit of time to transmit a packet (of fixed size) on a communication link. The link layer uses a window flow control protocol with a window size of N packets. Each packet causes an ack or a nak to be generated by the receiver, and ack/nak transmission times are negligible. Further, the round trip time on the link is equal to N units. Consider time i > N. If only acks have been received till time i(no naks), then the goodput evaluated at the transmitter at time i (in packets per unit time) isa)1 - N/ib)i/(N + i)c)1d)1 - e(i/N)Correct answer is 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for Suppose that it takes 1 unit of time to transmit a packet (of fixed size) on a communication link. The link layer uses a window flow control protocol with a window size of N packets. Each packet causes an ack or a nak to be generated by the receiver, and ack/nak transmission times are negligible. Further, the round trip time on the link is equal to N units. Consider time i > N. If only acks have been received till time i(no naks), then the goodput evaluated at the transmitter at time i (in packets per unit time) isa)1 - N/ib)i/(N + i)c)1d)1 - e(i/N)Correct answer is 'A'. Can you explain this answer?.
Solutions for Suppose that it takes 1 unit of time to transmit a packet (of fixed size) on a communication link. The link layer uses a window flow control protocol with a window size of N packets. Each packet causes an ack or a nak to be generated by the receiver, and ack/nak transmission times are negligible. Further, the round trip time on the link is equal to N units. Consider time i > N. If only acks have been received till time i(no naks), then the goodput evaluated at the transmitter at time i (in packets per unit time) isa)1 - N/ib)i/(N + i)c)1d)1 - e(i/N)Correct answer is 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE).
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Here you can find the meaning of Suppose that it takes 1 unit of time to transmit a packet (of fixed size) on a communication link. The link layer uses a window flow control protocol with a window size of N packets. Each packet causes an ack or a nak to be generated by the receiver, and ack/nak transmission times are negligible. Further, the round trip time on the link is equal to N units. Consider time i > N. If only acks have been received till time i(no naks), then the goodput evaluated at the transmitter at time i (in packets per unit time) isa)1 - N/ib)i/(N + i)c)1d)1 - e(i/N)Correct answer is 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Suppose that it takes 1 unit of time to transmit a packet (of fixed size) on a communication link. The link layer uses a window flow control protocol with a window size of N packets. Each packet causes an ack or a nak to be generated by the receiver, and ack/nak transmission times are negligible. Further, the round trip time on the link is equal to N units. Consider time i > N. If only acks have been received till time i(no naks), then the goodput evaluated at the transmitter at time i (in packets per unit time) isa)1 - N/ib)i/(N + i)c)1d)1 - e(i/N)Correct answer is 'A'. Can you explain this answer?, a detailed solution for Suppose that it takes 1 unit of time to transmit a packet (of fixed size) on a communication link. The link layer uses a window flow control protocol with a window size of N packets. Each packet causes an ack or a nak to be generated by the receiver, and ack/nak transmission times are negligible. Further, the round trip time on the link is equal to N units. Consider time i > N. If only acks have been received till time i(no naks), then the goodput evaluated at the transmitter at time i (in packets per unit time) isa)1 - N/ib)i/(N + i)c)1d)1 - e(i/N)Correct answer is 'A'. Can you explain this answer? has been provided alongside types of Suppose that it takes 1 unit of time to transmit a packet (of fixed size) on a communication link. The link layer uses a window flow control protocol with a window size of N packets. Each packet causes an ack or a nak to be generated by the receiver, and ack/nak transmission times are negligible. Further, the round trip time on the link is equal to N units. Consider time i > N. If only acks have been received till time i(no naks), then the goodput evaluated at the transmitter at time i (in packets per unit time) isa)1 - N/ib)i/(N + i)c)1d)1 - e(i/N)Correct answer is 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Suppose that it takes 1 unit of time to transmit a packet (of fixed size) on a communication link. The link layer uses a window flow control protocol with a window size of N packets. Each packet causes an ack or a nak to be generated by the receiver, and ack/nak transmission times are negligible. Further, the round trip time on the link is equal to N units. Consider time i > N. If only acks have been received till time i(no naks), then the goodput evaluated at the transmitter at time i (in packets per unit time) isa)1 - N/ib)i/(N + i)c)1d)1 - e(i/N)Correct answer is 'A'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.