The value of log2√3 (1728) can be found by using the properties of logarithms.

To solve this problem, we can break it down into smaller steps:

Step 1: Simplify the expression inside the logarithm
The expression inside the logarithm is √3 (1728). We can simplify this expression by finding the square root of 3 and multiplying it by 1728. The square root of 3 is approximately 1.732, so √3 (1728) is approximately 2980.8.

Step 2: Rewrite the expression using the properties of logarithms
The expression log2√3 (1728) can be rewritten as log2(√3) + log2(1728). This is because the logarithm of a product is equal to the sum of the logarithms of the individual factors.

Step 3: Evaluate each logarithm separately
We can now evaluate each logarithm separately using the base 2.

- log2(√3): To evaluate this logarithm, we need to find the power to which 2 must be raised to obtain the value of √3. Since √3 is approximately 1.732, we need to find the power to which 2 must be raised to obtain 1.732. This can be done by trial and error or by using a logarithm calculator. The closest power of 2 to 1.732 is 0.847, which means 2^0.847 is approximately equal to 1.732. Therefore, log2(√3) is approximately 0.847.

- log2(1728): To evaluate this logarithm, we need to find the power to which 2 must be raised to obtain the value of 1728. Since 2^10 is equal to 1024 and 2^11 is equal to 2048, we know that 1728 is between these two values. Therefore, log2(1728) is equal to 10.

Step 4: Add the values obtained from Step 3
Adding the values obtained from Step 3, we get 0.847 + 10 = 10.847.

Therefore, the value of log2√3 (1728) is approximately 10.847.

Since none of the given options match the calculated value, it seems there is an error in the question or the options provided.