Can you explain the answer of this question below:Ethyl methyl ether reacts with HBr to give:A:Methyl bromideB:Ethyl bromideC:Benzyl alcoholD:Diethyl bromideThe answer is a.

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Answer

This type of reaction follow the SN2 mechanism so according to SN2 mechanism the reactivity of the reactant is inversely proportional to steric hindrance... so in ethyl Methyl Ether steric hindrance on methyl is less as compared to ethyl... so according to this concept option A is correct

Answer

Answer

Ethers resist the attack of nucleophiles and bases. However, they are very good solvents in many organic reactions due to their ability to solvate cations by donating the electron pair from oxygen atom. Ethers are generally less reactive and react only with acids.

Answer

Introduction:

Ethyl methyl ether is an organic compound with the molecular formula C3H8O. It is commonly used as a solvent and is highly flammable. When ethyl methyl ether reacts with HBr (hydrogen bromide), it undergoes a substitution reaction resulting in the formation of a new compound.

Explanation:

Step 1: Formation of Carbocation

The first step in the reaction involves the protonation of ethyl methyl ether by HBr. This leads to the formation of a carbocation, which is a positively charged carbon atom. The oxygen atom in ethyl methyl ether acts as a nucleophile and donates a pair of electrons to the carbon atom, resulting in the formation of the carbocation.

Step 2: Nucleophilic Attack

In the next step, the bromide ion (Br-) acts as a nucleophile and attacks the carbocation. The bromide ion donates a pair of electrons to the positively charged carbon atom, forming a new bond.

Step 3: Formation of Methyl Bromide

The result of the nucleophilic attack is the formation of a new compound called methyl bromide. Methyl bromide has the molecular formula CH3Br and is a colorless gas. It is commonly used as a fumigant and as a precursor for the synthesis of other organic compounds.

Conclusion:

In summary, the reaction between ethyl methyl ether and HBr leads to the formation of methyl bromide. This reaction involves the protonation of ethyl methyl ether, the formation of a carbocation, and the nucleophilic attack of the bromide ion. Methyl bromide is the major product of this reaction.

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