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A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. In which of the following cases will the rope break. When the monkey
(a) Climbs up with an acceleration of 6 ms−2.
(a) Climbs up with an acceleration of 6 ms−2.
- a)640 N
- b)632 N
- c)760 N
- d)740 N
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A monkey of mass40kgclimbs on a rope which can stand a maximum tension...
Mass of the monkey, m = 40 kg
Acceleration due to gravity, g = 10 m/s
Maximum tension that the rope can bear, Tmax = 600 N
Acceleration of the monkey, a = 6 m/s2 upward
Using Newtons second law of motion, we can write the equation of motion as:
T mg = ma
T = m(g + a)
= 40 (10 + 6)
= 640 N
Since T > Tmax, the rope will break in this case.
Acceleration due to gravity, g = 10 m/s
Maximum tension that the rope can bear, Tmax = 600 N
Acceleration of the monkey, a = 6 m/s2 upward
Using Newtons second law of motion, we can write the equation of motion as:
T mg = ma
T = m(g + a)
= 40 (10 + 6)
= 640 N
Since T > Tmax, the rope will break in this case.
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Community Answer
A monkey of mass40kgclimbs on a rope which can stand a maximum tension...
First, we need to find the weight of the monkey, which is given by:
W = m * g
where W is weight, m is mass, and g is acceleration due to gravity (approximately 9.81 m/s^2).
W = 40 kg * 9.81 m/s^2 = 392.4 N
Next, we need to find the force exerted by the monkey on the rope, which is given by:
F = m * a
where F is force, m is mass, and a is acceleration.
F = 40 kg * 6 m/s^2 = 240 N
Since the tension in the rope cannot exceed 600 N, the force exerted by the monkey on the rope must be less than or equal to 600 N. Therefore, the tension in the rope is:
T = F + W = 240 N + 392.4 N = 632.4 N
Since the tension in the rope exceeds its maximum capacity of 600 N, the rope will break and the monkey will fall.
W = m * g
where W is weight, m is mass, and g is acceleration due to gravity (approximately 9.81 m/s^2).
W = 40 kg * 9.81 m/s^2 = 392.4 N
Next, we need to find the force exerted by the monkey on the rope, which is given by:
F = m * a
where F is force, m is mass, and a is acceleration.
F = 40 kg * 6 m/s^2 = 240 N
Since the tension in the rope cannot exceed 600 N, the force exerted by the monkey on the rope must be less than or equal to 600 N. Therefore, the tension in the rope is:
T = F + W = 240 N + 392.4 N = 632.4 N
Since the tension in the rope exceeds its maximum capacity of 600 N, the rope will break and the monkey will fall.
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A monkey of mass40kgclimbs on a rope which can stand a maximum tension of600N. In which of the following cases will the rope break. When the monkey(a) Climbs up with an acceleration of6ms−2.a)640 Nb)632 Nc)760 Nd)740 NCorrect answer is option 'A'. Can you explain this answer?
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A monkey of mass40kgclimbs on a rope which can stand a maximum tension of600N. In which of the following cases will the rope break. When the monkey(a) Climbs up with an acceleration of6ms−2.a)640 Nb)632 Nc)760 Nd)740 NCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A monkey of mass40kgclimbs on a rope which can stand a maximum tension of600N. In which of the following cases will the rope break. When the monkey(a) Climbs up with an acceleration of6ms−2.a)640 Nb)632 Nc)760 Nd)740 NCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A monkey of mass40kgclimbs on a rope which can stand a maximum tension of600N. In which of the following cases will the rope break. When the monkey(a) Climbs up with an acceleration of6ms−2.a)640 Nb)632 Nc)760 Nd)740 NCorrect answer is option 'A'. Can you explain this answer?.
A monkey of mass40kgclimbs on a rope which can stand a maximum tension of600N. In which of the following cases will the rope break. When the monkey(a) Climbs up with an acceleration of6ms−2.a)640 Nb)632 Nc)760 Nd)740 NCorrect answer is option 'A'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A monkey of mass40kgclimbs on a rope which can stand a maximum tension of600N. In which of the following cases will the rope break. When the monkey(a) Climbs up with an acceleration of6ms−2.a)640 Nb)632 Nc)760 Nd)740 NCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A monkey of mass40kgclimbs on a rope which can stand a maximum tension of600N. In which of the following cases will the rope break. When the monkey(a) Climbs up with an acceleration of6ms−2.a)640 Nb)632 Nc)760 Nd)740 NCorrect answer is option 'A'. Can you explain this answer?.
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