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Energy of H–atom in the ground state is -13.6 eV , Hence energy in the second excited state is–
a) -1.51 eV
b) -3.4 eV
c) -6.8 eV 
d) -4.3 eV
Correct answer is 'A'. Can you explain this answer ?
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Energy of H–atom in the ground state is -13.6 eV , Hence energy in the...
The formula to calculate the energy is minus 13.6 multiply by z2 divided by n2.Here in second excited state n is equal to 3 and z for hydrogen is 1. So -13.6/9 = -1.51 ev
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Energy of H–atom in the ground state is -13.6 eV , Hence energy in the...
Hlo ashutosh...yes the right answer is c option coz the formula to calculate the energy is minus 13.6 multiply by z^2 divided by n^2....here in second excited state n is equal to 3...and z for hydrogen is 1...so -13.6 by 9...gives -1.51 ev.... hope u get it...
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Energy of H–atom in the ground state is -13.6 eV , Hence energy in the...


Energy of H-atom in Ground State

- The energy of the ground state of a hydrogen atom is given as -13.6 eV. This value represents the lowest energy level that an electron can occupy in the atom.

Energy in the Second Excited State

- To calculate the energy in the second excited state, we need to understand the energy levels of the hydrogen atom. The energy levels of the hydrogen atom are given by the formula En = -13.6/n^2 eV, where n is the principal quantum number.
- For the second excited state, n = 3 (since the ground state is n = 1 and the first excited state is n = 2).
- Plugging in n = 3 into the formula, we get E3 = -13.6/3^2 = -13.6/9 = -1.51 eV.

Conclusion

- Therefore, the energy in the second excited state of a hydrogen atom is -1.51 eV. This corresponds to the energy level when the electron is in the third orbit around the nucleus.
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Energy of H–atom in the ground state is -13.6 eV , Hence energy in the second excited state is–a)-1.51 eVb)-3.4 eVc)-6.8 eVd)-4.3 eVCorrect answer is 'A'. Can you explain this answer ?
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