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If x + 2 is a factor of x3 – 2ax2 + 16, then value of a is
- a)3
- b)1
- c)4
- d)2
Correct answer is 'B'. Can you explain this answer?
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Verified Answer
If x + 2 is a factor of x3– 2ax2+ 16, then value of a isa)3b)1c)...
use factor theorem as x+2 is factor of
x³-2ax²+16 so put x = -2 and equate the equation to 0
so putting x = -2
(-2)³-2a(-2)²+16 =0
-8-8a+16=0
-8a = -8
a = 8/8= 1
So,
a = 1
Most Upvoted Answer
If x + 2 is a factor of x3– 2ax2+ 16, then value of a isa)3b)1c)...
X + 2 is equal to zero which is equal to minus 2 then we will put -2 where ever X is written and put it equal to zero to find the value of a
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Community Answer
If x + 2 is a factor of x3– 2ax2+ 16, then value of a isa)3b)1c)...
Since X+2 is a factor of x³-2ax²+16......Let p(x) = x³-2ax²+16.......x = -2 is zero of p(x).........p(-2)= (-2)³-2a(-2)²+16.........p(-2)=-8-8a+16.......0= 8-8a...... -8 = -8a.......-8/-8 = a...... 1=a.So, the answer is a = 1
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