A reaction 3A+2B+C=1.5D+E occurs in a reactor at steady state. What wi...
Explanation: NA/ND= (rate of disappearance of A)/(rate of appearance of D)
= -3/1.5
= -2.
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A reaction 3A+2B+C=1.5D+E occurs in a reactor at steady state. What wi...
Steady State Reaction and Flux Ratio
Steady State Reaction:
In a steady-state reaction, the rate of formation of reactants is equal to the rate of consumption, and there is no net accumulation of any component in the reactor. It is a balanced state where the reaction proceeds without any change in composition or concentration.
Flux Ratio:
The flux ratio is the ratio of the molar flow rate of two species in a chemical reaction. It is used to analyze the reaction rate and the rate of consumption or formation of the species.
Given Reaction:
3A + 2B + C = 1.5D + E
To determine the flux ratio NA/ND, we need to find the molar flow rate of species A and D.
Molar Flow Rate:
Molar flow rate is the number of moles of a substance that passes through a unit of cross-sectional area per unit of time. It is calculated by multiplying the volumetric flow rate by the molar concentration of the species.
Assumptions:
Assuming that the reactor operates under steady-state conditions, the molar flow rate of species A is equal to the molar flow rate of species E.
Flux Ratio Calculation:
The molar flow rate of species D can be calculated using the stoichiometry of the given reaction.
3 moles of A react to produce 1.5 moles of D, therefore, the molar flow rate of D is half of the molar flow rate of A.
NA/ND = molar flow rate of A/molar flow rate of D
Since the molar flow rate of D is half of the molar flow rate of A, the flux ratio can be calculated as follows:
NA/ND = 2/1
NA/ND = -2 (negative sign indicates that A and D are reacting in opposite directions)
Therefore, the correct answer is option A, i.e., -2.