Can you explain the answer of this question below:A racing car has a u...
Given:Acceleration = 6 m/s^2Time = 10 secAs car start from rest so intial velocity will be zero.u = 0S = ut + 1/2(at^2)S = 0 + 1/2 x 6 x 100S = 300 m.
Can you explain the answer of this question below:A racing car has a u...
**Given Information:**
- Acceleration (a) = 6 m/s^2
- Time (t) = 10 s
**Formula:**
The distance covered by an object with uniform acceleration can be calculated using the equation:
\[d = ut + \frac{1}{2}at^2\]
where:
- d = distance covered
- u = initial velocity (which is assumed to be zero in this case)
- a = acceleration
- t = time
**Calculation:**
Substituting the given values into the formula, we get:
\[d = 0 \cdot 10 + \frac{1}{2} \cdot 6 \cdot (10)^2\]
\[d = 0 + \frac{1}{2} \cdot 6 \cdot 100\]
\[d = 0 + 3 \cdot 100\]
\[d = 300\]
Therefore, the racing car will cover a distance of 300 meters in 10 seconds.
**Explanation:**
When an object undergoes uniform acceleration, its velocity changes at a constant rate. In this case, the racing car has a uniform acceleration of 6 m/s^2. This means that its velocity increases by 6 m/s every second.
To calculate the distance covered by the car in 10 seconds, we use the formula \(d = ut + \frac{1}{2}at^2\). Since the car starts from rest (initial velocity, u, is zero), the equation simplifies to \(d = \frac{1}{2}at^2\).
By substituting the given values into the formula, we find that the distance covered by the car is 300 meters.
Therefore, option A (300m) is the correct answer.