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Can you explain the answer of this question below:
A compound is soluble in conc. H₂SO₄, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound is
  • A:
    primary alcohol
  • B:
    tertiary alcohol
  • C:
    alkene
  • D:
    ether
The answer is a.
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Can you explain the answer of this question below:A compound is solubl...
Explanation:
The given compound is soluble in conc. HSO4 which indicates the presence of an alcohol group. The compound does not decolourise bromine in carbon tetrachloride which means it does not contain a carbon-carbon double bond. Further, the compound is oxidized by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque which indicates the presence of a primary alcohol.

Reasoning:
- Solubility in conc. H2SO4 indicates the presence of an alcohol group.
- The absence of decolourisation of bromine in carbon tetrachloride indicates the absence of a carbon-carbon double bond.
- The oxidation of the compound by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque indicates the presence of a primary alcohol.

Conclusion:
Based on the above observations, the original compound is a primary alcohol.
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Can you explain the answer of this question below:A compound is solubl...
Primary alcohol..
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Can you explain the answer of this question below:A compound is soluble in conc. H₂SO₄, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound isA: primary alcohol B: tertiary alcohol C: alkene D: ether The answer is a.
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Can you explain the answer of this question below:A compound is soluble in conc. H₂SO₄, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound isA: primary alcohol B: tertiary alcohol C: alkene D: ether The answer is a. for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Can you explain the answer of this question below:A compound is soluble in conc. H₂SO₄, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound isA: primary alcohol B: tertiary alcohol C: alkene D: ether The answer is a. covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Can you explain the answer of this question below:A compound is soluble in conc. H₂SO₄, it does not decolourise bromine in carbon tetrachloride but is oxidised by chromic anhydride in aqueous sulphuric acid within two seconds, turning orange solution to blue, green and then opaque. The original compound isA: primary alcohol B: tertiary alcohol C: alkene D: ether The answer is a..
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